Math Problem Statement
A parachutist that is 70 kg drops from a helicopter 2000 meters high and falls under the influence of gravity . Assume the force due to air resistance is proportional to the velocity of the parachutist, with the proportionality constant b1=30 n-sec/m when the chute is closed and b2=90 n-sec/m when the chute is open. If the chute does not open until the velocity of the parachutist is 15m/sec, after how many seconds will the parachutist reach the ground? Assume gravity is 9.81 m/sec^2
Solution
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Math Problem Analysis
Mathematical Concepts
Differential Equations
Physics (Mechanics)
Exponential Decay
Formulas
F = mg - b1v
dv/dt = g - (b1/m)v
v(t) = (mg/b1)(1 - e^(-(b1/m)t))
v(t) = (mg/b2)(1 - e^(-(b2/m)(t - t1)))
Theorems
Newton's Second Law of Motion
Exponential Growth and Decay
Suitable Grade Level
Undergraduate Physics or Advanced High School
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