Math Problem Statement

A.

-1010-1010xy

A coordinate system has a horizontal x-axis labeled from negative 10 to 10 in increments of 1 and a vertical y-axis labeled from negative 10 to 10 in increments of 1. Upper A parabola that opens upwards has vertex left parenthesis negative 3 comma negative 4 right parenthesis and passes through the points left parenthesis negative 4 comma negative 3 right parenthesis and left parenthesis negative 1 comma 0 right parenthesis .

B.

-1010-1010xy

A coordinate system has a horizontal x-axis labeled from negative 10 to 10 in increments of 1 and a vertical y-axis labeled from negative 10 to 10 in increments of 1. Upper A parabola that opens downwards has vertex left parenthesis negative 3 comma negative 4 right parenthesis and passes through the points left parenthesis negative 4 comma negative 5 right parenthesis and left parenthesis negative 1 comma negative 8 right parenthesis .

C.

-1010-1010xy

A coordinate system has a horizontal x-axis labeled from negative 10 to 10 in increments of 1 and a vertical y-axis labeled from negative 10 to 10 in increments of 1. Upper A parabola that opens downwards has vertex left parenthesis 3 comma negative 4 right parenthesis and passes through the points left parenthesis 2 comma negative 5 right parenthesis and left parenthesis 5 comma negative 8 right parenthesis .

D.

-1010-1010xy

Solution

Let's break down each of the cases to formulate the equations of the parabolas.

General form of a parabola equation:

A parabola with a vertex (h,k)(h, k) can be expressed as: y=a(xh)2+ky = a(x - h)^2 + k where (h,k)(h, k) is the vertex, and aa determines the direction and width of the parabola.

Case A:

  • Vertex: (3,4)(-3, -4)
  • Direction: Opens upwards
  • Points: Passes through (4,3)(-4, -3) and (1,0)(-1, 0)
  1. Equation form: y=a(x+3)24y = a(x + 3)^2 - 4 We use (h,k)=(3,4)(h, k) = (-3, -4).

  2. Find aa using the point (4,3)(-4, -3): 3=a(4+3)24-3 = a(-4 + 3)^2 - 4 3=a(1)24-3 = a(1)^2 - 4 a=1a = 1 So the equation is: y=(x+3)24y = (x + 3)^2 - 4

Case B:

  • Vertex: (3,4)(-3, -4)
  • Direction: Opens downwards
  • Points: Passes through (4,5)(-4, -5) and (1,8)(-1, -8)
  1. Equation form: y=a(x+3)24y = a(x + 3)^2 - 4 Again, using the vertex (3,4)(-3, -4).

  2. Find aa using the point (4,5)(-4, -5): 5=a(4+3)24-5 = a(-4 + 3)^2 - 4 5=a(1)24-5 = a(1)^2 - 4 a=1a = -1 The equation is: y=(x+3)24y = -(x + 3)^2 - 4

Case C:

  • Vertex: (3,4)(3, -4)
  • Direction: Opens downwards
  • Points: Passes through (2,5)(2, -5) and (5,8)(5, -8)
  1. Equation form: y=a(x3)24y = a(x - 3)^2 - 4 We use (h,k)=(3,4)(h, k) = (3, -4).

  2. Find aa using the point (2,5)(2, -5): 5=a(23)24-5 = a(2 - 3)^2 - 4 5=a(1)24-5 = a(1)^2 - 4 a=1a = -1 The equation is: y=(x3)24y = -(x - 3)^2 - 4


Would you like to go deeper into any of the cases?

Here are 5 related questions:

  1. How do you determine if a parabola opens upwards or downwards?
  2. How do you find the vertex of a parabola from its equation?
  3. What is the significance of the constant aa in a parabola equation?
  4. How can you use two points on a parabola to determine its equation?
  5. What is the effect of shifting the vertex on the shape of the parabola?

Tip: The vertex form of a parabola y=a(xh)2+ky = a(x - h)^2 + k is very helpful in graphing and finding properties such as the vertex and direction of opening.

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Math Problem Analysis

Mathematical Concepts

Algebra
Quadratic Functions
Parabolas

Formulas

Parabola vertex form: y = a(x - h)^2 + k
Equation solving using given points

Theorems

Properties of Parabolas
Vertex Form of a Parabola

Suitable Grade Level

Grades 9-11