Math Problem Statement
For the following set of data identify any outlier, if there is one. 840, 296, 157, 750, 5,580, 400.
Solution
To identify outliers in the data set , we will use the Interquartile Range (IQR) method.
Steps to Identify Outliers:
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Sort the Data: Arrange the data in ascending order.
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Calculate the Quartiles:
- Median (Q2): The middle value of the sorted data:
- Lower Quartile (Q1): Median of the lower half:
- Upper Quartile (Q3): Median of the upper half:
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Calculate the IQR:
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Determine Outlier Bounds:
- Lower Bound: (no lower outliers as data can't go below 0).
- Upper Bound: .
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Identify Outliers:
- Any data point less than the lower bound or greater than the upper bound is an outlier.
- Observing the data: All values except are within the range . Therefore, is an outlier.
Conclusion:
The only outlier in the data is .
Would you like further details or have any questions?
Related Questions:
- What is the significance of IQR in outlier detection?
- How would the presence of multiple outliers affect statistical measures like mean and variance?
- Could the Z-score method detect as an outlier in this data set?
- How can removing outliers impact the analysis of a data set?
- What are other methods for identifying outliers besides IQR and Z-scores?
Tip:
Outlier detection is vital for improving data quality and ensuring statistical analyses are not skewed by extreme values.
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Math Problem Analysis
Mathematical Concepts
Statistics
Outlier Detection
Interquartile Range (IQR)
Formulas
Median (Q2): (n/2th value if n is odd or average of (n/2)th and (n/2 + 1)th values if n is even)
Lower Quartile (Q1): Median of lower half of the data
Upper Quartile (Q3): Median of upper half of the data
IQR = Q3 - Q1
Outlier Bounds: Lower Bound = Q1 - 1.5 * IQR, Upper Bound = Q3 + 1.5 * IQR
Theorems
IQR Method for Outlier Detection
Suitable Grade Level
Grades 8-10
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