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Let's break down the problem step by step:

### Problem Restatement:
- A piece of even-weight cargo has the following dimensions:
  - Length: \( 13 \, \text{m} \)
  - Width: \( 3.18 \, \text{m} \)
  - Height: \( 2.65 \, \text{m} \)
  - Weight: \( 55 \, \text{tons} \)
- The goods are to be loaded onto an **N17AK flat car**.
- The flat car's specifications:
  - Floor height: \( 1211 \, \text{mm} = 1.211 \, \text{m} \)
  - Length: \( 13 \, \text{m} \)
  - Distance between two kingpins (axles): \( 9 \, \text{m} \)

### Goal:
Determine the "out-of-gauge" grade, which likely refers to assessing whether the cargo exceeds standard clearances for transport, both horizontally and vertically.

### Step 1: Check if the cargo fits within the flat car dimensions

- **Length:** 
  The cargo length is \( 13 \, \text{m} \), which perfectly matches the flat car's length of \( 13 \, \text{m} \).

- **Width:**
  The cargo width is \( 3.18 \, \text{m} \). Typical railcar loading limits vary, but a standard flatcar width usually accommodates loads around \( 3 \, \text{m} \). This cargo slightly exceeds that, so it might be classified as "out-of-gauge" horizontally. Additional clearance calculations would be needed.

### Step 2: Vertical clearance considerations

The total height of the cargo on the flat car will be the sum of the flat car floor height and the cargo height:
\[
\text{Total height} = 1.211 \, \text{m} + 2.65 \, \text{m} = 3.861 \, \text{m}
\]

Railway clearances can vary, but a typical rail clearance envelope in many countries might be around \( 4.5 \, \text{m} \) from the rail to the top of the load. In this case, the total height of \( 3.861 \, \text{m} \) would likely fit within the vertical clearance, assuming standard conditions.

### Step 3: Weight considerations

The cargo weighs \( 55 \, \text{tons} \). Standard flatcars can handle heavy loads, but the weight distribution and axle load must be considered. The information doesn't provide axle load limits, but given the length and weight, this needs to be calculated against specific rail car capacities.

### Conclusion:

- **Length:** Fits exactly.
- **Width:** Exceeds standard loading gauge, making it "out-of-gauge" horizontally.
- **Height:** Fits within typical clearance, so not "out-of-gauge" vertically.
- **Weight:** Would require checking against the specific weight distribution capacity of the flat car.

Would you like to dive deeper into any specific part, such as weight distribution or detailed clearance standards?

Here are five related questions to consider:
1. What are the specific weight capacity limits of the N17AK flat car?
2. How do rail regulations define "out-of-gauge" cargo in terms of width limits?
3. What impact does the width exceeding the standard have on transportation planning?
4. Is there any need for special permits or escort vehicles for out-of-gauge loads?
5. What are the safety precautions for transporting out-of-gauge cargo?

**Tip:** Always consider both horizontal and vertical clearances when planning cargo transport by rail. These determine if a load is "out-of-gauge."

A piece of even-weight cargo is 13m in length, 3.18m in width and 2.65m in height, and it weighs 55 tons. Load the goods directly on a N17AK flat car. Determine the out-of-gauge grade of the goods.

Determine the out-of-gauge grade for a 13m cargo loaded on an N17AK flat car with 55-ton weight. Analyze vertical and horizontal clearances, weight distribution, and fit within the standard railcar dimensions.

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