To solve this problem, we need to compare the probabilities of different events when randomly selecting a chip numbered 1 through 100. The probabilities of each event depend on the number of favorable outcomes for that event.

Let's define the events more clearly and calculate their probabilities:

Assumptions:

1. Event A: Probability of selecting a chip with a number divisible by 2 (even numbers).
2. Event B: Probability of selecting a chip with a number divisible by 3.
3. Event C: Probability of selecting a chip with a number divisible by 5.
4. Event D: Probability of selecting a chip with a number divisible by 10.

Let's find the probabilities:

1. Event A: Divisible by 2 (Even Numbers)
   Numbers divisible by 2 are: 2, 4, 6, ..., 100.
   Total numbers divisible by 2: $\frac{100}{2} = 50$.
   Probability of Event A = $\frac{50}{100} = 0.5$.

2. Event B: Divisible by 3
   Numbers divisible by 3 are: 3, 6, 9, ..., 99.
   Total numbers divisible by 3: $\frac{100}{3} \approx 33$.
   Probability of Event B = $\frac{33}{100} = 0.33$.

3. Event C: Divisible by 5
   Numbers divisible by 5 are: 5, 10, 15, ..., 100.
   Total numbers divisible by 5: $\frac{100}{5} = 20$.
   Probability of Event C = $\frac{20}{100} = 0.2$.

4. Event D: Divisible by 10
   Numbers divisible by 10 are: 10, 20, 30, ..., 100.
   Total numbers divisible by 10: $\frac{100}{10} = 10$.
   Probability of Event D = $\frac{10}{100} = 0.1$.

Ordering the Probabilities:

Now we compare the probabilities:

• Event A: 0.5
• Event B: 0.33
• Event C: 0.2
• Event D: 0.1

The order of the events from greatest to least probability is:

1. Event A: Divisible by 2 (0.5)
2. Event B: Divisible by 3 (0.33)
3. Event C: Divisible by 5 (0.2)
4. Event D: Divisible by 10 (0.1)

Would you like more details or have any questions?

Related Questions:

1. What is the probability of selecting a number divisible by both 2 and 3?
2. How many numbers between 1 and 100 are divisible by both 2 and 5?
3. If a number is selected randomly, what is the probability it is a prime number?
4. What is the probability of selecting a number that is divisible by either 3 or 5?
5. How would the probabilities change if the numbers were from 1 to 200 instead?

Tip:

When dealing with probability problems, it is crucial to carefully count the favorable outcomes and ensure the total possible outcomes are correctly considered.