### Problem Summary:
There are 30 people who need to travel, and they have three types of vehicles to choose from:

1. **Large Bus:**
   - Capacity: 30 people
   - Cost: 10 Yuan per hour

2. **Small Bus:**
   - Capacity: 8 people
   - Cost: 8 Yuan per hour

3. **Car:**
   - Capacity: 4 people
   - Cost: 5 Yuan per hour

### Question:
**How should the vehicles be chosen to be the most economical?**

### Solution Approach:
To solve this problem, we need to find a combination of vehicles that can accommodate all 30 people at the lowest total cost per hour.

#### Calculating the Cost for Different Combinations:

1. **Option 1: One Large Bus**
   - 1 Large Bus can accommodate all 30 people.
   - Total Cost: \(10\) Yuan per hour.

2. **Option 2: Only Small Buses**
   - Each small bus can accommodate 8 people.
   - To accommodate 30 people, we need \(\lceil 30 / 8 \rceil = 4\) small buses.
   - Total Cost: \(4 \times 8 = 32\) Yuan per hour.

3. **Option 3: Only Cars**
   - Each car can accommodate 4 people.
   - To accommodate 30 people, we need \(\lceil 30 / 4 \rceil = 8\) cars.
   - Total Cost: \(8 \times 5 = 40\) Yuan per hour.

4. **Mixed Combinations:**


This problem involves optimizing the selection of vehicles for 30 people using a large bus, small buses, and cars to minimize total cost per hour. The solution explores discrete math and optimization, using ceiling functions to calculate the number of vehicles required for various combinations. Suitable for Grades 9-12 students.

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