Math Problem Statement
Solution
Let's break down the information given to form equations for this problem:
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Let , , and represent the units of products A, B, and C, respectively.
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Total units produced constraint:
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Profit constraint:
- Profit per unit for A, B, and C is $1, $2, and $3, respectively.
- Total profit = $20,000.
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Cost constraint:
- Fixed costs are $16,000.
- Production costs per unit for A, B, and C are $4, $5, and $7, respectively.
- Total cost (including fixed cost) = $68,000. Simplifying, we get:
We now have a system of three equations:
x + y + z = 9000 \\ x + 2y + 3z = 20000 \\ 4x + 5y + 7z = 52000 \end{cases}$$ Let's solve this system of equations to find $$x$$, $$y$$, and $$z$$.The solution to the system of equations is: - $$x = 3000$$ units of product A, - $$y = 1000$$ units of product B, - $$z = 5000$$ units of product C. Therefore, the manufacturer should produce: - 3000 units of product A, - 1000 units of product B, - 5000 units of product C. Would you like a detailed explanation of the steps taken, or do you have any questions? ### Related Questions 1. How would the solution change if the profit per unit of product A increased? 2. What if the production cost per unit of product C was reduced to $6? 3. How would the equations change if the fixed cost increased to $18,000? 4. What is the impact on production numbers if the profit goal was raised to $25,000? 5. Could these constraints lead to an optimal solution using linear programming? ### Tip In problems like this, setting up clear equations from the constraints is key to solving systems accurately.Ask a new question for Free
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Math Problem Analysis
Mathematical Concepts
Algebra
System of Linear Equations
Formulas
Total units equation: x + y + z = 9000
Profit equation: 1x + 2y + 3z = 20000
Cost equation: 4x + 5y + 7z = 52000
Theorems
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Suitable Grade Level
Grades 10-12
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