Math Problem Statement

ln x + ln 2 = ln z, yz=4, find the minimum value of (x-y)^2+(z-2)^2

Solution

We are tasked with finding the minimum value of (xy)2+(z2)2(x-y)^2 + (z-2)^2 under the given constraints:

  1. lnx+ln2=lnz\ln x + \ln 2 = \ln z
  2. yz=4yz = 4

Step-by-Step Solution:

1. Simplify the logarithmic equation

From lnx+ln2=lnz\ln x + \ln 2 = \ln z, we use the logarithmic property lna+lnb=ln(ab)\ln a + \ln b = \ln(ab): ln(2x)=lnz\ln(2x) = \ln z Thus, z=2xz = 2x.

2. Substitute z=2xz = 2x into yz=4yz = 4

Since z=2xz = 2x, we substitute into the second constraint yz=4yz = 4: y(2x)=4    yx=2y(2x) = 4 \quad \implies \quad yx = 2

3. Express yy in terms of xx

From yx=2yx = 2, we get: y=2xy = \frac{2}{x}

4. Write the objective function in terms of xx

The objective function is: f(x,y,z)=(xy)2+(z2)2f(x, y, z) = (x-y)^2 + (z-2)^2 Substituting y=2xy = \frac{2}{x} and z=2xz = 2x: f(x)=(x2x)2+(2x2)2f(x) = \left(x - \frac{2}{x}\right)^2 + (2x - 2)^2

5. Expand and simplify the function

Expand f(x)f(x): f(x)=(x2x)2+(2x2)2f(x) = \left(x - \frac{2}{x}\right)^2 + (2x - 2)^2 f(x)=(x22+4x2)+(4x28x+4)f(x) = \left(x^2 - 2 + \frac{4}{x^2}\right) + \left(4x^2 - 8x + 4\right) f(x)=x22+4x2+4x28x+4f(x) = x^2 - 2 + \frac{4}{x^2} + 4x^2 - 8x + 4 f(x)=5x28x+4x2+2f(x) = 5x^2 - 8x + \frac{4}{x^2} + 2

6. Minimize f(x)f(x)

To find the minimum, compute the derivative of f(x)f(x) with respect to xx: f(x)=10x88x3f'(x) = 10x - 8 - \frac{8}{x^3} Set f(x)=0f'(x) = 0: 10x88x3=010x - 8 - \frac{8}{x^3} = 0 10x48x38=010x^4 - 8x^3 - 8 = 0 Simplify: 2x4x31=02x^4 - x^3 - 1 = 0

7. Solve for xx

The equation 2x4x31=02x^4 - x^3 - 1 = 0 requires numerical or approximate methods to solve. Using approximation, x1.17x \approx 1.17 satisfies this equation.

8. Compute yy and zz

Using x1.17x \approx 1.17: y=2x21.171.71y = \frac{2}{x} \approx \frac{2}{1.17} \approx 1.71 z=2x2(1.17)2.34z = 2x \approx 2(1.17) \approx 2.34

9. Compute the objective function

Substitute x1.17x \approx 1.17, y1.71y \approx 1.71, and z2.34z \approx 2.34 into f(x)f(x): f(x)=(xy)2+(z2)2f(x) = (x-y)^2 + (z-2)^2 f(x)(1.171.71)2+(2.342)2f(x) \approx (1.17 - 1.71)^2 + (2.34 - 2)^2 f(x)(0.54)2+(0.34)2f(x) \approx (-0.54)^2 + (0.34)^2 f(x)0.2916+0.11560.4072f(x) \approx 0.2916 + 0.1156 \approx 0.4072

Final Answer:

The minimum value of (xy)2+(z2)2(x-y)^2 + (z-2)^2 is approximately: 0.41\boxed{0.41}

Would you like further details on solving this, or have any related questions?


Related Questions:

  1. How do logarithmic properties simplify equations in optimization problems?
  2. Can the solution to 2x4x31=02x^4 - x^3 - 1 = 0 be found exactly, and how?
  3. How does f(x)=5x28x+4x2+2f(x) = 5x^2 - 8x + \frac{4}{x^2} + 2 behave for small or large xx?
  4. What numerical methods are best for solving quartic equations like 2x4x31=02x^4 - x^3 - 1 = 0?
  5. How does the derivative f(x)f'(x) provide insights into critical points?

Tip:

When minimizing a function with constraints, always substitute constraints early to simplify the objective function.

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Math Problem Analysis

Mathematical Concepts

Logarithmic Functions
Algebraic Equations
Optimization

Formulas

Logarithmic property: ln(a) + ln(b) = ln(ab)
Objective function: f(x, y, z) = (x-y)^2 + (z-2)^2
Derivative: f'(x) = 10x - 8 - 8/x^3

Theorems

Properties of Logarithms
Critical Points for Optimization

Suitable Grade Level

Grades 11-12