Math Problem Statement
Brittany and Wiyot wants to raise iguanas in a rectangular field with four internal partitions as shown. If the area of the field must be square feet, what dimensions will require the least fencing? What should the length and width be?
Solution
To solve this problem, we need to minimize the total length of fencing required, given the fixed area of the field. Here's the step-by-step process:
Step 1: Define the Variables
- Let the length of the field be .
- Let the width of the field be .
- The area of the rectangular field is given by:
The total fencing includes the perimeter and the internal partitions.
Step 2: Total Fencing Requirement
- The field has 2 lengths and 6 widths (4 internal partitions add to the width fencing), so the total fencing is:
Step 3: Express One Variable in Terms of the Other
From the area constraint:
Step 4: Substitute into the Fencing Equation
Substitute into :
Simplify:
Step 5: Minimize the Fencing Function
To minimize , take the derivative with respect to , set it to 0, and solve for :
Set :
Multiply through by :
Solve for :
Take the square root:
Step 6: Solve for
Using :
Step 7: Final Dimensions
- Length:
- Width:
Substitute with the given area to get the exact dimensions. If you provide the value of , I can calculate the specific dimensions for you.
Would you like me to proceed with numerical calculations? Let me know!
Questions:
- What is the exact area of the field in square feet?
- Do you want a detailed explanation of the optimization process?
- Should we explore how the internal partitions affect the fencing further?
- Would you like to see a diagram of the fencing setup for better visualization?
- Should we consider any constraints or practical adjustments in the dimensions?
Tip:
When minimizing functions in geometry problems, ensure you consider constraints properly to avoid missing real-world implications.
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Math Problem Analysis
Mathematical Concepts
Optimization
Geometry
Calculus
Formulas
Area of a rectangle: A = L × W
Fencing requirement: F = 2L + 6W
Relationship between width and length using area: W = A / L
Minimization function: F = 2L + 6(A / L)
Theorems
First derivative test for optimization
Suitable Grade Level
Grades 11-12