Math Problem Statement

จงแสดงว่า OLS จะไม่สามารถประมาณค่าแบบจำลองดังกล่าวได้ โดยให้พิสูจน์ในรูปแบบเมทริกซ์ให้ชัดเจนพร้อมเหตุผลประกอบ

จงแสดงว่า OLS จะไม่สามารถประมาณค่าแบบจำลองดังกล่าวได้ โดยให้พิสูจน์ในรูปแบบเมทริกซ์ให้ชัดเจนพร้อมเหตุผลประกอบ

Solution

The question involves a matrix form of the Ordinary Least Squares (OLS) model, written as:

y=Xβ+μy = X\beta + \mu

where:

  • yy is a vector of observed dependent variables,
  • XX is a matrix of independent variables (with each column corresponding to a predictor, and each row to an observation),
  • β\beta is a vector of coefficients to be estimated, and
  • μ\mu is a vector of errors.

To show why OLS cannot estimate this model, we need to prove it using matrix algebra. Here's the detailed explanation:

Step 1: Normal Equation for OLS

OLS estimates are derived by minimizing the residual sum of squares, which leads to the normal equation: β^=(XTX)1XTy\hat{\beta} = (X^T X)^{-1} X^T y This formula requires that the matrix XTXX^T X (the product of the transpose of XX and XX) must be invertible. If XTXX^T X is not invertible (i.e., singular), the OLS estimates cannot be computed.

Step 2: Checking XTXX^T X

From the matrix in the question, we see that the first column of XX consists of 1's (this represents the intercept term), and the rest of the columns represent the independent variables XijX_{ij}.

For OLS estimation to work, the matrix XTXX^T X must be full-rank (i.e., the columns of XX must be linearly independent). If the columns of XX are linearly dependent, then XTXX^T X will be singular, and the inverse (XTX)1(X^T X)^{-1} will not exist, making OLS estimation impossible.

Step 3: Linearly Dependent Columns

In the matrix provided, notice that there is a column of 1's (for the intercept), and there may be other independent variables. However, if any of the independent variables are collinear (i.e., one variable can be expressed as a linear combination of others), this leads to multicollinearity.

In particular, if any of the columns of XX are perfectly collinear with others, then XTXX^T X will not be invertible. This situation could arise if, for example:

  • Some variables are duplicates of others,
  • Some variables are linear transformations of others,
  • Or the number of variables exceeds the number of observations (i.e., more columns than rows in XX).

Conclusion:

In this case, the OLS estimator β^=(XTX)1XTy\hat{\beta} = (X^T X)^{-1} X^T y cannot be computed because XTXX^T X is singular due to linear dependence in the columns of XX. Hence, OLS cannot estimate the model.


Would you like me to go deeper into any part of this proof or elaborate on any step?

Related Questions:

  1. What are some methods to detect multicollinearity in real datasets?
  2. How can we remedy the problem of multicollinearity in a regression model?
  3. Can you explain why XTXX^T X needs to be invertible in more detail?
  4. What are some alternative estimation methods when OLS fails due to singularity of XTXX^T X?
  5. How does the inclusion of an intercept affect the rank of XTXX^T X?

Tip:

When dealing with multicollinearity, techniques like Ridge Regression or Principal Component Analysis (PCA) can help mitigate the issue by reducing the impact of linearly dependent variables.

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Math Problem Analysis

Mathematical Concepts

Ordinary Least Squares
Matrix Algebra
Linear Dependence
Multicollinearity

Formulas

y = Xβ + μ
β̂ = (XᵀX)⁻¹Xᵀy
Condition for invertibility: XᵀX must be full rank

Theorems

OLS estimator derivation
Invertibility condition of matrix XᵀX
Multicollinearity leading to singular matrix

Suitable Grade Level

Undergraduate level (Econometrics/Linear Algebra)