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The given problem involves determining the current (I) flowing through a resistor based on a voltage-current (V-I) graph. The relationship between voltage (V) and current (I) follows Ohm's law:

\[
V = I \times R
\]

Where:
- \(V\) is the voltage (in volts),
- \(I\) is the current (in amperes), and
- \(R\) is the resistance (in ohms).

### Step 1: Find the Resistance (R)
From the graph, we can see that when the current (\(I\)) is 0.02 amperes (or 20 mA), the voltage (\(V\)) is 2.5 volts. Using these values, we can calculate the resistance (\(R\)):

\[
R = \frac{V}{I} = \frac{2.5 \, \text{V}}{0.02 \, \text{A}} = 125 \, \Omega
\]

### Step 2: Calculate the Current for \(V = 5.0\) Volts
Now, the problem states that the voltage is 5.0 volts. Using the same resistance (\(R = 125 \, \Omega\)), we can calculate the current (\(I\)) using Ohm's law:

\[
I = \frac{V}{R} = \frac{5.0 \, \text{V}}{125 \, \Omega} = 0.04 \, \text{A} = 40 \, \text{mA}
\]

### Final Answer:
The current flowing through the resistor is **40 mA**. Hence, the correct answer is:

**d. 40 mA**

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Would you like a more detailed explanation, or do you have any questions?

Here are some related questions:
1. How does the resistance affect the slope of a V-I graph?
2. What would happen to the current if the resistance doubled?
3. How is Ohm's law applied to more complex circuits?
4. What are the units of resistance and why are they important?
5. How does the temperature affect the resistance of a material?

**Tip:** Always check the slope of a V-I graph, as it directly gives the resistance in linear circuits.

Dari percobaan hubungan tegangan (V) dengan kuat arus (I) pada resistor, dihasilkan grafik V-I pada gambar di bawah. Jika V = 5,0 volt, maka besar kuat arus yang mengalir adalah ....

Learn how to calculate the current through a resistor using Ohm's law and a voltage-current graph. Given a graph showing a V-I relationship, determine the current when the voltage is 5.0 volts. Suitable for high school physics students.

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