Math Problem Statement

Cermati deret bilangan berikut ini: 28, 1/12, -14, 1/6, 7, 1/4, -7/2, 1/3, P, Q. Nilai dari P dan Q yang paling logis secara berurutan adalah ....

Solution

Let's solve the sequence to find the logical values of PP and QQ.

Given sequence: 28,112,16,14,12,73,P,Q28, \frac{1}{12}, \frac{1}{6}, \frac{1}{4}, \frac{1}{2}, \frac{7}{3}, P, Q

Step 1: Analyze the Sequence Observing the sequence, the first step is to identify a pattern or a rule that changes one term to the next.

Step 2: Find a Pattern We see that the sequence transitions from integers to fractions and back. The sequence of fractions (112\frac{1}{12} to 12\frac{1}{2}) seems to increase by multiplying by a constant factor, and the 73\frac{7}{3} appears to be a bridge from fractions back towards whole numbers.

We need to first determine the multiplier:

  • From 112\frac{1}{12} to 16\frac{1}{6}, the term doubles.
  • From 16\frac{1}{6} to 14\frac{1}{4}, the term multiplies by 32\frac{3}{2}.
  • From 14\frac{1}{4} to 12\frac{1}{2}, it doubles.

Let's check the multiplier consistency:

  • 112×2=16\frac{1}{12} \times 2 = \frac{1}{6}
  • 16×32=14\frac{1}{6} \times \frac{3}{2} = \frac{1}{4}
  • 14×2=12\frac{1}{4} \times 2 = \frac{1}{2}

It appears the multiplication alternates between 2 and 32\frac{3}{2}. However, from 12\frac{1}{2} to 73\frac{7}{3}, a different rule may apply because the nature of the sequence shifts significantly, potentially resuming integer values.

Step 3: Project the Pattern If we assume a continued multiplication but need to determine the next factors for PP and QQ, let's first reverse-engineer from 73\frac{7}{3}:

  • Assuming 12×k=73\frac{1}{2} \times k = \frac{7}{3} gives k=143k = \frac{14}{3}.
  • If we continue the sequence for PP using a multiplier, the next logical step is to multiply 73\frac{7}{3} by 22, given the observed alternating pattern:
    • P=73×2=143P = \frac{7}{3} \times 2 = \frac{14}{3}

Step 4: Calculate QQ If the pattern persists (multiplying by 32\frac{3}{2} next):

  • Q=143×32=7Q = \frac{14}{3} \times \frac{3}{2} = 7

Thus, P=143P = \frac{14}{3} and Q=7Q = 7.

Would you like further details on any step or have any other questions about this sequence?

Potential questions to expand your understanding:

  1. Why does the sequence start with an integer and switch to fractions?
  2. Could there be an alternative pattern that fits the given sequence?
  3. How can we confirm that the sequence indeed alternates multipliers?
  4. What would the next number be after QQ if the pattern continued?
  5. How do sequences like this apply in real-world scenarios?

Tip: When dealing with sequences, always look for consistency in the applied rules across several terms to validate your hypothesis about the pattern.

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Math Problem Analysis

Mathematical Concepts

Number Sequences
Pattern Recognition
Fractions

Formulas

General term of sequence formula

Theorems

Arithmetic and Geometric Progressions

Suitable Grade Level

Grades 9-12