Math Problem Statement

5.      For the given series ∑𝟒𝒊=𝟎(𝟐𝒊−𝟏 − 𝟏),            state the following:   a.      Number of terms in the series     

Solution

Let's analyze the given series:

i=04(2i11)\sum_{i=0}^{4} (2i - 1 - 1)

Step 1: Understanding the series expression

The series is summing up the expression 2i112i - 1 - 1 from i=0i = 0 to i=4i = 4. To simplify:

2i11=2i22i - 1 - 1 = 2i - 2

So the series becomes:

i=04(2i2)\sum_{i=0}^{4} (2i - 2)

Step 2: Identifying the number of terms

The summation goes from i=0i = 0 to i=4i = 4, inclusive. To determine the number of terms in the series, we count the values of ii.

The values of ii are: i=0,1,2,3,4i = 0, 1, 2, 3, 4

Thus, there are 5 terms in the series.

Answer:

The number of terms in the series is 5.

Would you like to compute the sum of this series or explore more properties of it?

Related Questions:

  1. How do you calculate the sum of this series?
  2. What happens if we extend the upper limit of the summation to a higher number?
  3. How do you write this series in closed form?
  4. What is the general form of an arithmetic series?
  5. How would you find the sum of the first nn terms for a different series?

Tip: In any summation of the form i=mn\sum_{i=m}^{n}, the number of terms is simply nm+1n - m + 1, counting the inclusive range!

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Math Problem Analysis

Mathematical Concepts

Summation
Arithmetic Series

Formulas

Sum of an arithmetic series: S = n(a_1 + a_n)/2

Theorems

Arithmetic progression

Suitable Grade Level

Grades 9-12