Math Problem Statement

How many terms are there in the expansion of (x + y)^100 after like terms are collected?

Solution

To determine the number of distinct terms in the expansion of (x+y)100(x + y)^{100} after collecting like terms, we use the concept of binomial expansion.

The general expansion of (x+y)n(x + y)^n is given by: (x+y)n=k=0n(nk)xnkyk(x + y)^n = \sum_{k=0}^{n} \binom{n}{k} x^{n-k} y^k

Each term in the expansion is of the form xnkykx^{n-k} y^k, where kk ranges from 0 to nn. For each unique pair of powers (nk,k)(n - k, k), we get a distinct term. Here, since n=100n = 100, kk can range from 0 to 100, providing 101 possible terms (one for each integer value of kk).

Thus, there are 101 distinct terms in the expansion of (x+y)100(x + y)^{100} after like terms are collected.

Would you like more details on binomial expansion?

Here are some related questions:

  1. How can we calculate specific coefficients in the binomial expansion of (x+y)100(x + y)^{100}?
  2. What is the general form of a term in a binomial expansion?
  3. How does the binomial theorem apply to cases where xx or yy has a coefficient other than 1?
  4. Can we determine the middle term in the expansion of (x+y)100(x + y)^{100}?
  5. How does the binomial expansion apply to negative or fractional exponents?

Tip: In a binomial expansion, the number of distinct terms is always n+1n + 1 for (x+y)n(x + y)^n, because each term corresponds to a unique power combination of xx and yy.

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Math Problem Analysis

Mathematical Concepts

Binomial Expansion
Combinatorics

Formulas

(x + y)^n = ∑ (n choose k) x^(n-k) y^k

Theorems

Binomial Theorem

Suitable Grade Level

Grades 10-12