Math Problem Statement

•Box A weighs 50 N and rests on a table. A rope that connects Eboxes A and B drapes over a pulley so that box B hangs 2 above the table, as shown in the figure. The pulley and rope are massless, and the pulley is frictionless. © Macmillan B A What force n, does the table exert on box A if box B weighs 20 N? Assume that the positive direction is upwards. n1 = & TOOLS X10% What force n2 does the table exert on box A if box B weighs 40 N? Assume that the positive direction is upwards. 12 = What force n3 does the table exert on box A if box B weighs 60 N? Assume that the positive direction is upwards.

Solution

To solve the problem, let's analyze the forces acting on box A in different scenarios based on the weight of box B.

Step-by-step Analysis:

  1. System Overview:

    • Box A rests on a table, and a rope connects it to box B, which hangs off the table through a pulley.
    • The weight of box A is given as 50 N.
    • The system is in equilibrium (no acceleration), meaning that the net force on each box is zero.
  2. Calculating the Normal Force nn on Box A:

    • The weight of Box A WAW_A = 50 N acts downward.
    • The tension TT in the rope, which is equal to the weight of box B WBW_B, acts horizontally on box A.
    • Since there is no horizontal motion, the horizontal forces on Box A cancel out.
    • The vertical forces acting on box A include:
      • The weight of Box A (WA=50W_A = 50 N) acting downward.
      • The normal force nn from the table acting upward.
      • If box B is heavier or lighter, the rope will either pull box A slightly downwards or upwards, affecting the net force on the table.
  3. Force Equilibrium for Each Case:

Case 1: Box B Weighs 20 N

  • The vertical forces on box A are:
    • Weight of Box A: 50N50 \, \text{N} (downward)
    • Table’s normal force n1n_1 (upward)

Because box B is pulling downwards (20 N), the tension in the rope reduces the effective weight of box A on the table: n1=WAWB=50N20N=30Nn_1 = W_A - W_B = 50 \, \text{N} - 20 \, \text{N} = 30 \, \text{N}

Case 2: Box B Weighs 40 N

  • Using the same analysis: n2=WAWB=50N40N=10Nn_2 = W_A - W_B = 50 \, \text{N} - 40 \, \text{N} = 10 \, \text{N}

Case 3: Box B Weighs 60 N

  • This time, the weight of Box B is greater than Box A, which means it will pull box A slightly upwards, reducing the force the table exerts: n3=WAWB=50N60N=10Nn_3 = W_A - W_B = 50 \, \text{N} - 60 \, \text{N} = -10 \, \text{N}

Final Answers:

  • n1=30Nn_1 = 30 \, \text{N} (for WB=20NW_B = 20 \, \text{N})
  • n2=10Nn_2 = 10 \, \text{N} (for WB=40NW_B = 40 \, \text{N})
  • n3=10Nn_3 = -10 \, \text{N} (for WB=60NW_B = 60 \, \text{N})

The negative sign indicates that in the third case, the table is not exerting a normal force on Box A; instead, the table is being pulled slightly upwards by Box A.

If you'd like further clarification or a detailed diagram, feel free to ask!

Related Questions:

  1. What is the tension in the rope for each case?
  2. How would the normal force change if the mass of the pulley is not negligible?
  3. What is the acceleration of the system if Box B is heavier than Box A?
  4. How would friction between the table and Box A affect the system?
  5. What would happen if the pulley had a non-negligible mass?

Tip:

Always consider both vertical and horizontal force components separately when dealing with systems involving pulleys and connected masses.

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Math Problem Analysis

Mathematical Concepts

Newton's Laws of Motion
Forces
Equilibrium

Formulas

n = W_A - W_B

Theorems

Newton's First Law (Equilibrium)
Newton's Third Law (Action-Reaction)

Suitable Grade Level

Grades 9-12