Math Problem Statement

Sketch the region corresponding to the statement P(z > 1.4). Sketch the region corresponding to the statement P(z < c) = 0.25.

Solution

In the image, you are working on normal distribution problems involving ZZ-scores.

1st Question:

The statement is P(z>1.4)P(z > 1.4), meaning you are asked to shade the region to the right of z=1.4z = 1.4 under the standard normal distribution curve. Currently, it seems you have the region to the left of a negative value shaded, which is incorrect for this question.

What to do:

  • Adjust the shading option to "Right of a value".
  • Drag the arrow to the position z=1.4z = 1.4 and shade everything to the right of it.

2nd Question:

The statement is P(z<c)=0.25P(z < c) = 0.25, meaning you're asked to find the value of cc such that the area to the left of cc under the curve is 0.25. Currently, the arrow is placed at z=1.5z = -1.5, which likely corresponds to an area greater than 0.25.

What to do:

  • Drag the arrow to a value of zz that corresponds to an area of 0.25. This value should be around z=0.674z = -0.674, as that corresponds to 25% of the data being to the left.

Would you like detailed steps on how to solve these using the Z-table or normal distribution properties?

Related Questions:

  1. How do you calculate the area under a normal curve using Z-scores?
  2. What is the significance of the 0.25 value in normal distributions?
  3. How can you use a Z-table to find corresponding areas or Z-scores?
  4. Why is the Z-score of 1.4 used in the first problem?
  5. How does symmetry of the normal distribution help with probability calculations?

Tip:

When working with standard normal distribution curves, make sure you understand whether you're shading to the left or right of the Z-score. This can significantly affect your results!

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Math Problem Analysis

Mathematical Concepts

Probability
Normal Distribution
Z-Scores

Formulas

P(z > 1.4)
P(z < c) = 0.25

Theorems

Properties of Standard Normal Distribution
Z-Score Table Lookup

Suitable Grade Level

Grades 11-12