Math Problem Statement

A certain standardized test has scores which range from 0 to 500, with decimal scores possible. Scores on the exam are normally distributed with a mean of 316 and a standard deviation of 44.

What proportion of students taking the exam receive a score that is within 72 points of the mean?

Round your answer to four (4) decimal places. (e.g. 0.1234)

Solution

We are asked to find the proportion of students who receive a score within 72 points of the mean on a standardized test where the scores are normally distributed.

Given information:

  • Mean (μ\mu) = 316
  • Standard deviation (σ\sigma) = 44
  • We need the proportion of students with scores within 72 points of the mean, i.e., between 31672316 - 72 and 316+72316 + 72.

Step 1: Define the bounds

The lower bound is: 31672=244316 - 72 = 244 The upper bound is: 316+72=388316 + 72 = 388 Thus, we are looking for the probability that a score is between 244 and

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Statistics
Normal Distribution
Z-Scores

Formulas

Z = (X - μ) / σ
Proportion = P(a < X < b) where a and b are bounds

Theorems

Empirical Rule (68-95-99.7 Rule)
Properties of the Normal Distribution

Suitable Grade Level

Grades 10-12