Math Problem Statement

A population of values has a normal distribution with and . You intend to draw a random sample of size .

Find the probability that a single randomly selected value is less than 158.7. P(X < 158.7) =

Find the probability that a sample of size is randomly selected with a mean less than 158.7. P(M < 158.7) =

Enter your answers as numbers accurate to 4 decimal places. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.

Solution

To solve these problems, we'll need to use the properties of the normal distribution and the concept of the z-score. However, you're missing key pieces of information:

  1. The mean (μ\mu) of the population.
  2. The standard deviation (σ\sigma) of the population.
  3. The sample size (nn).

Let me outline how to solve these problems:

Part 1: Probability for a Single Randomly Selected Value P(X<158.7)P(X < 158.7)

We can find this probability using the z-score formula for a single value:

z=Xμσz = \frac{X - \mu}{\sigma}

Where:

  • X=158.7X = 158.7,
  • μ=population mean\mu = \text{population mean},
  • σ=population standard deviation\sigma = \text{population standard deviation}.

Once we calculate the z-score, we can look up the cumulative probability from the standard normal distribution table or use a calculator to find P(X<158.7)P(X < 158.7).

Part 2: Probability for a Sample Mean P(M<158.7)P(M < 158.7)

For a sample of size nn, the distribution of the sample mean MM is normally distributed with mean μ\mu and standard deviation σn\frac{\sigma}{\sqrt{n}} (called the standard error).

We calculate the z-score for the sample mean using:

z=Mμσnz = \frac{M - \mu}{\frac{\sigma}{\sqrt{n}}}

Where:

  • M=158.7M = 158.7,
  • μ=population mean\mu = \text{population mean},
  • σ=population standard deviation\sigma = \text{population standard deviation},
  • n=sample sizen = \text{sample size}.

Then, just like in part 1, we can find the cumulative probability for this z-score.


If you provide the values of μ\mu, σ\sigma, and nn, I can compute the exact probabilities for you. Would you like to proceed with that?


Here are some related questions to further your understanding:

  1. How does the sample size affect the standard error of the mean?
  2. What is the difference between P(X<158.7)P(X < 158.7) and P(M<158.7)P(M < 158.7)?
  3. Why do we use the standard normal distribution for finding probabilities?
  4. How would the probability change if the population had a different standard deviation?
  5. Can you explain why the sample mean has a smaller variability than individual values?

Tip: The larger the sample size, the smaller the standard error, which makes the sample mean distribution more concentrated around the population mean.

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Math Problem Analysis

Mathematical Concepts

Normal Distribution
Probability
Z-Score
Sampling Distribution

Formulas

Z-score for a single value: z = (X - μ) / σ
Z-score for a sample mean: z = (M - μ) / (σ / sqrt(n))

Theorems

Central Limit Theorem
Standard Normal Distribution

Suitable Grade Level

College level (Statistics and Probability)