Math Problem Statement

A population is distributed normally with a mean of 120 and standard deviation 20.

Compute the P(X < 100)

Solution

To compute the probability P(X<100)P(X < 100) for a normally distributed population with a mean μ=120\mu = 120 and standard deviation σ=20\sigma = 20, we will standardize the variable using the z-score formula:

Z=XμσZ = \frac{X - \mu}{\sigma}

Here:

  • X=100X = 100
  • μ=120\mu = 120
  • σ=20\sigma = 20

Now, substitute the values into the formula:

Z=10012020=2020=1Z = \frac{100 - 120}{20} = \frac{-20}{20} = -1

Next, we need to find the probability corresponding to Z<1Z < -1 using the standard normal distribution table or a calculator.

The probability P(Z<1)P(Z < -1) corresponds to approximately 0.1587.

Thus, P(X<100)0.1587P(X < 100) \approx 0.1587.

Summary:

The probability that XX is less than 100 is approximately 0.1587, or 15.87%.

Would you like more details or further explanation?

Related Questions:

  1. What is P(X>140)P(X > 140) for the same distribution?
  2. How do you compute P(100<X<140)P(100 < X < 140)?
  3. How do you standardize a normal distribution?
  4. What is the cumulative probability for Z=0Z = 0?
  5. How do you interpret the z-score of a data point?

Tip: To find probabilities in a normal distribution, always standardize the variable first using the z-score formula.

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Math Problem Analysis

Mathematical Concepts

Statistics
Probability
Normal Distribution
Z-scores

Formulas

Z = (X - μ) / σ
P(Z < z-value) for standard normal distribution

Theorems

Empirical Rule (68-95-99.7 rule)
Standard Normal Distribution

Suitable Grade Level

Grades 10-12