Math Problem Statement
In City A, monthly rainfall was recorded to be normally distributed with mean 226 mm and standard deviation 52 mm .
Solution
Given that the monthly rainfall in City A follows a normal distribution with a mean (μ) of 226 mm and a standard deviation (σ) of 52 mm, you can calculate various probabilities and percentiles for this distribution.
For example, with a normal distribution:
- 68% of data lies within 1 standard deviation of the mean, i.e., between: \quad \text{and} \quad \mu + \sigma = 226 + 52 = 278 \, \text{mm}$$
- 95% of data lies within 2 standard deviations, i.e., between: \quad \text{and} \quad \mu + 2\sigma = 226 + 2(52) = 330 \, \text{mm}$$
- 99.7% of data lies within 3 standard deviations, i.e., between: \quad \text{and} \quad \mu + 3\sigma = 226 + 3(52) = 382 \, \text{mm}$$
Do you want to calculate any specific probabilities, like how likely it is for the rainfall to exceed or fall below a certain value? Let me know if you'd like more details or clarifications on how to proceed with further calculations!
Here are some related questions you might explore:
- What is the probability that the rainfall is less than 200 mm in a month?
- What is the probability that rainfall is
Ask a new question for Free
By Image
Drop file here or Click Here to upload
Math Problem Analysis
Mathematical Concepts
Statistics
Normal Distribution
Probability
Formulas
68-95-99.7 Rule (Empirical Rule)
Standard deviation formula
Probability density function for a normal distribution
Theorems
Central Limit Theorem
Empirical Rule
Suitable Grade Level
Grades 10-12
Related Recommendation
Normal Distribution and Empirical Rule for Rainfall Amounts
Normal Distribution and Rainfall: Understanding the Empirical Rule
Understanding Normal Distribution: Annual Rainfall Example
Mean and Standard Deviation of Yearly Rainfall Using Chebyshev’s Theorem
Understanding Normal Distribution: Rainfall Data and Empirical Rule