Math Problem Statement

In City A, monthly rainfall was recorded to be normally distributed with mean 226 mm and standard deviation 52 mm .

Solution

Given that the monthly rainfall in City A follows a normal distribution with a mean (μ) of 226 mm and a standard deviation (σ) of 52 mm, you can calculate various probabilities and percentiles for this distribution.

For example, with a normal distribution:

  1. 68% of data lies within 1 standard deviation of the mean, i.e., between: \quad \text{and} \quad \mu + \sigma = 226 + 52 = 278 \, \text{mm}$$
  2. 95% of data lies within 2 standard deviations, i.e., between: \quad \text{and} \quad \mu + 2\sigma = 226 + 2(52) = 330 \, \text{mm}$$
  3. 99.7% of data lies within 3 standard deviations, i.e., between: \quad \text{and} \quad \mu + 3\sigma = 226 + 3(52) = 382 \, \text{mm}$$

Do you want to calculate any specific probabilities, like how likely it is for the rainfall to exceed or fall below a certain value? Let me know if you'd like more details or clarifications on how to proceed with further calculations!

Here are some related questions you might explore:

  1. What is the probability that the rainfall is less than 200 mm in a month?
  2. What is the probability that rainfall is

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Math Problem Analysis

Mathematical Concepts

Statistics
Normal Distribution
Probability

Formulas

68-95-99.7 Rule (Empirical Rule)
Standard deviation formula
Probability density function for a normal distribution

Theorems

Central Limit Theorem
Empirical Rule

Suitable Grade Level

Grades 10-12