Math Problem Statement

In the United States, 21% of adults ages 25 and older have never been married, more than double the figure recorded for 1960. Select a random sample of 50 U.S. adults ages 25 and older and let X = the number of individuals in the sample who have never married.

(a) Calculate the mean and standard deviation of the appropriate normal distribution.

Mean =

10.5

Correct Answer

individuals

(Do not round.)

Standard Deviation =

2.881

Correct Answer

individuals

(Round to 3 decimal places.)

(b) Use this normal distribution to calculate the probability that at most 5 of the individuals in the sample have never been married.

Probability =

0.0413

Incorrect Answer

(Round to 4 decimal places. Leave your answer in decimal form.)

Solution

Let's break down the problem step by step.

(a) Calculating the mean and standard deviation

You are dealing with a binomial distribution in this case, since you are selecting a sample of 50 adults and checking whether each individual has never been married. We can approximate this binomial distribution as a normal distribution using the central limit theorem because the sample size is large.

Given:

  • Proportion of adults who have never been married: p=0.21p = 0.21
  • Sample size: n=50n = 50

The mean and standard deviation for a binomial distribution are given by:

Mean=μ=np\text{Mean} = \mu = n \cdot p Standard deviation=σ=np(1p)\text{Standard deviation} = \sigma = \sqrt{n \cdot p \cdot (1 - p)}

Step 1: Calculate the mean.

μ=500.21=10.5\mu = 50 \cdot 0.21 = 10.5

Step 2: Calculate the standard deviation.

σ=500.21(10.21)=500.210.79\sigma = \sqrt{50 \cdot 0.21 \cdot (1 - 0.21)} = \sqrt{50 \cdot 0.21 \cdot 0.79}

σ=500.1659=8.2952.881\sigma = \sqrt{50 \cdot 0.1659} = \sqrt{8.295} \approx 2.881

Thus:

  • Mean = 10.5
  • Standard deviation ≈ 2.881

(b) Calculating the probability

We want to calculate the probability that at most 5 individuals in the sample have never been married. Since we are approximating a binomial distribution with a normal distribution, we can use the following formula for the probability:

P(X5)P(Z5μσ)P(X \leq 5) \approx P\left( Z \leq \frac{5 - \mu}{\sigma} \right)

Where:

  • ZZ is the standard normal random variable (Z-score).

Step 1: Calculate the Z-score.

Z=510.52.881=5.52.8811.910Z = \frac{5 - 10.5}{2.881} = \frac{-5.5}{2.881} \approx -1.910

Step 2: Look up the Z-score in the standard normal distribution table or use a calculator to find the probability.

For Z=1.910Z = -1.910, the corresponding probability is approximately 0.0281 (this is the area to the left of Z=1.910Z = -1.910).

Thus, the probability that at most 5 individuals in the sample have never been married is approximately 0.0281 (rounded to 4 decimal places).

Final Answers:

  • (a) Mean = 10.5 individuals
  • (a) Standard Deviation ≈ 2.881 individuals
  • (b) Probability ≈ 0.0281

Would you like to go over any of the steps in more detail, or do you have any other questions?

Here are some related questions to explore further:

  1. How does the Central Limit Theorem apply to binomial distributions?
  2. How would the probability change if the sample size was larger or smaller?
  3. What is the relationship between the binomial distribution and the normal distribution?
  4. How do we calculate probabilities for continuous distributions like the normal distribution?
  5. Can we calculate the probability for "at most" using other methods besides the Z-score?

Tip: When approximating a binomial distribution with a normal distribution, remember to use a continuity correction (adjusting the value by 0.5) when you're working with discrete values like 5 or 6, but it's often ignored for large sample sizes.

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Math Problem Analysis

Mathematical Concepts

Binomial Distribution
Normal Distribution
Central Limit Theorem
Probability Theory

Formulas

Mean = n * p
Standard Deviation = sqrt(n * p * (1 - p))
Z = (X - μ) / σ
P(X ≤ x) ≈ P(Z ≤ (x - μ) / σ)

Theorems

Central Limit Theorem

Suitable Grade Level

Grades 11-12