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The image contains the following problem statement:

> "A 0.15 kg car accelerates at 20 m/s² due to the combined actions of two forces. If the second force acts to the right with 12 N, calculate the net force and direction of the car."

Let's solve this problem using the GRESA method, which stands for Given, Required, Equation, Solution, and Answer.

### Step 1: Given (G)
- Mass of the car, \( m = 0.15 \, \text{kg} \)
- Acceleration, \( a = 20 \, \text{m/s}^2 \)
- Second force to the right, \( F_2 = 12 \, \text{N} \)

### Step 2: Required (R)
- Find the net force (\( F_{net} \)) and its direction.

### Step 3: Equation (E)
The net force can be found using Newton's second law of motion:
\[
F_{net} = m \times a
\]

### Step 4: Solution (S)
1. Calculate the net force using the given mass and acceleration:
   \[
   F_{net} = 0.15 \, \text{kg} \times 20 \, \text{m/s}^2 = 3 \, \text{N}
   \]

2. Since \( F_{net} = F_1 + F_2 \) and we know \( F_{net} = 3 \, \text{N} \), solve for the first force (\( F_1 \)):
   \[
   F_{1} = F_{net} - F_{2} = 3 \, \text{N} - 12 \, \text{N}
   \]

This calculation leads to:
   \[
   F_{1} = -9 \, \text{N}
   \]

The negative sign indicates that \( F_{1} \) is acting in the opposite direction to \( F_2 \).

### Step 5: Answer (A)
The net force acting on the car is \( 3 \, \text{N} \) to the left, as the leftward force dominates due to \( F_1 \).

Would you like more details on any of these steps or do you have any specific questions?

Here are some related questions you might find useful:
1. How would the solution change if the mass of the car was different?
2. What would happen if the forces acted in the same direction?
3. Can you explain why the direction of the net force is to the left?
4. How would friction affect the motion of the car in this scenario?
5. What if the acceleration was different, how would that change the net force?

**Tip:** Remember, in problems involving multiple forces, the direction and magnitude of each force are crucial for determining the net force correctly.

A 0.15 kg car accelerates at 20 m/s² due to the combined actions of two forces. If the second force acts to the right with 12 N, calculate the net force and direction of the car.

This problem involves calculating the net force acting on a 0.15 kg car accelerating at 20 m/s² with two forces, one acting to the right with 12 N. Learn to apply Newton's second law and vector addition to determine the net force and its direction.

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