The problem asks to fill in the missing numbers in the multiplication and addition process for the calculation $24 \times 19$. Here's how the solution unfolds:

Step-by-step Solution:

1. Set up the multiplication:

   • The number $24$ is multiplied by $19$, which can be broken down as: $24 \times 19 = (24 \times 10) + (24 \times 9)$

2. Break down and solve each part:

   • $24 \times 9 = 216$
   • $24 \times 10 = 240$

3. Fill in the missing values in the problem:

   • From the first row: $24 \times 9 = 216$, so the digit missing in $\boxed{2}16$ is $2$.
   • The second part of the multiplication: $24 \times 10 = 240$, so the missing digit in $24\boxed{0}$ is $0$.
   • Adding $216 + 240 = 456$, confirms that the final missing digit in $456$ is $6$.

Final Answer:

• Missing numbers: $\boxed{2}, \boxed{0}, \boxed{6}$.

Would you like a more detailed explanation or additional examples?

Related Questions:

1. How is breaking down multiplication into parts (e.g., $10 + 9$) useful in solving problems?
2. What are other methods to solve $24 \times 19$ mentally or on paper?
3. How can multiplication with carrying be applied to larger numbers?
4. Why does multiplying by $10$ simply involve adding a zero to the end of the number?
5. How can you verify multiplication results through estimation?

Tip:

When solving multiplication problems like $24 \times 19$, splitting numbers into parts (e.g., $10 + 9$) makes calculations more manageable and reduces errors.