Math Problem Statement

(10 + 7i) · (10 + 7i) =

Solution

The given problem asks you to multiply two complex numbers and express the result in terms of ii. The expression is:

(10+7i)(10+7i)(10 + 7i) \cdot (10 + 7i)

This is equivalent to squaring the complex number 10+7i10 + 7i:

(10+7i)2(10 + 7i)^2

To expand this, we use the distributive property (FOIL):

(10+7i)(10+7i)=102+2(10)(7i)+(7i)2(10 + 7i)(10 + 7i) = 10^2 + 2(10)(7i) + (7i)^2

Now, calculating each term:

  • 102=10010^2 = 100
  • 2(10)(7i)=140i2(10)(7i) = 140i
  • (7i)2=49i2(7i)^2 = 49i^2

Recall that i2=1i^2 = -1, so:

49i2=49(1)=4949i^2 = 49(-1) = -49

Now, combine all the terms:

100+140i49=(10049)+140i=51+140i100 + 140i - 49 = (100 - 49) + 140i = 51 + 140i

Thus, the final simplified result is:

51+140i51 + 140i

Would you like further explanation on this? Here are a few questions related to complex number multiplication that might help you:

  1. What is the general formula for multiplying two complex numbers?
  2. How does the imaginary unit ii behave under multiplication?
  3. How does i2=1i^2 = -1 affect complex number operations?
  4. Can complex numbers be visualized geometrically in the complex plane?
  5. How do powers of ii cycle through different values?

Tip: When multiplying complex numbers, always apply the distributive property and remember that i2=1i^2 = -1.

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Math Problem Analysis

Mathematical Concepts

Complex Numbers
Algebra
Imaginary Numbers

Formulas

FOIL Method for binomials
i^2 = -1

Theorems

Distributive Property
Imaginary Unit i Behavior

Suitable Grade Level

Grades 10-12