Math Problem Statement

Solve the following mathematical exercises: 1. (α) 5 / 5 = ? 2. (β) 3 * 3 * 6 * 5 * 6 = ? 3. (γ) β * β * β * β * β = ? 4. (δ) 6 + 6 + ... + 6 (32 additions) = ? 5. (ε) 2011 * 2011 * 2011 * 2011 * 2011 = ?

Solution

Let's go through the exercises in the image one by one:

  1. (α) 55=?\frac{5}{5} = ?: 55=1\frac{5}{5} = 1

  2. (β) 33656=?3 \cdot 3 \cdot 6 \cdot 5 \cdot 6 = ?: 33=9,96=54,545=270,2706=16203 \cdot 3 = 9,\quad 9 \cdot 6 = 54,\quad 54 \cdot 5 = 270,\quad 270 \cdot 6 = 1620 So the result is: 16201620

  3. (γ) βββββ=?β \cdot β \cdot β \cdot β \cdot β = ?: Here, assuming ββ represents a number or variable that is not provided, you would multiply ββ five times. The result would be: β5β^5

  4. (δ) 6+6++66 + 6 + \dots + 6 (32 times): This is equivalent to: 326=19232 \cdot 6 = 192

  5. (ε) 20112011201120112011=?2011 \cdot 2011 \cdot 2011 \cdot 2011 \cdot 2011 = ?: This would be: 201152011^5 Without full expansion, this remains as 20112011 raised to the power of 5.

Let me know if you would like more details on any of these solutions or need further assistance!

Here are some related questions:

  1. What is the value of 333663 \cdot 3 \cdot 3 \cdot 6 \cdot 6?
  2. What does it mean when we write aa\frac{a}{a} for any a0a \neq 0?
  3. How do you calculate the power of a variable, like β5β^5?
  4. How can you quickly calculate the sum of repeated additions like in problem (δ)?
  5. What is 201132011^3?

Tip: When dealing with large powers, you can simplify calculations by using properties of exponents or logarithms.

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Math Problem Analysis

Mathematical Concepts

Division
Multiplication
Exponents
Repeated Addition
Powers

Formulas

a / a = 1 for any non-zero a
Multiplication of multiple numbers
Exponentiation β^n means multiplying β n times
Sum of repeated additions: n * x

Theorems

Fundamental Theorem of Arithmetic (for multiplication)
Exponentiation Rules

Suitable Grade Level

Grades 6-8