Math Problem Statement

Jenelle bought a home for $360,000, paying 16% as a down payment, and financing the rest at 7% interest for 30 years. Round your answers to the nearest cent.

How much money did Jenelle pay as a down payment? $  

What was the original amount financed? $  

What is her monthly payment? $  

If Jenelle makes these payments every month for thirty years, determine the total amount of money she will spend on this home. Include the down payment in your answer. $  

Solution

Let's solve this step-by-step.

1. Down Payment Calculation:

Jenelle paid 16% as a down payment. We can calculate that using the formula: Down Payment=Price of the Home×Down Payment Percentage\text{Down Payment} = \text{Price of the Home} \times \text{Down Payment Percentage} Down Payment=360,000×0.16=57,600\text{Down Payment} = 360,000 \times 0.16 = 57,600

So, Jenelle paid $57,600 as a down payment.


2. Original Amount Financed:

The amount financed is the cost of the home minus the down payment: Amount Financed=360,00057,600=302,400\text{Amount Financed} = 360,000 - 57,600 = 302,400

So, the original amount financed is $302,400.


3. Monthly Payment Calculation:

To calculate Jenelle's monthly mortgage payment, we use the formula for a fixed-rate mortgage payment (using the amortization formula): M=P×r×(1+r)n(1+r)n1M = \frac{P \times r \times (1 + r)^n}{(1 + r)^n - 1} Where:

  • MM is the monthly payment,
  • PP is the principal (amount financed = $302,400),
  • rr is the monthly interest rate (annual interest rate ÷ 12 months = 0.07 ÷ 12 = 0.0058333),
  • nn is the total number of payments (30 years × 12 months = 360 months).

Substituting the values: M=302,400×0.0058333×(1+0.0058333)360(1+0.0058333)3601M = \frac{302,400 \times 0.0058333 \times (1 + 0.0058333)^{360}}{(1 + 0.0058333)^{360} - 1}

Calculating this step-by-step:

M302,400×0.0058333×9.40979.40971M \approx \frac{302,400 \times 0.0058333 \times 9.4097}{9.4097 - 1} M302,400×0.05487788.4097M \approx \frac{302,400 \times 0.0548778}{8.4097} M16,598.248.40971,973.17M \approx \frac{16,598.24}{8.4097} \approx 1,973.17

So, Jenelle's monthly payment is approximately $1,973.17.


4. Total Amount Spent on the Home:

The total amount Jenelle will spend over 30 years is the sum of her monthly payments over 360 months plus the down payment: Total Amount Spent=(Monthly Payment×360)+Down Payment\text{Total Amount Spent} = (\text{Monthly Payment} \times 360) + \text{Down Payment} Total Amount Spent=(1,973.17×360)+57,600\text{Total Amount Spent} = (1,973.17 \times 360) + 57,600 Total Amount Spent=710,341.20+57,600=767,941.20\text{Total Amount Spent} = 710,341.20 + 57,600 = 767,941.20

So, Jenelle will spend a total of $767,941.20 on her home over 30 years, including the down payment.


Summary of Results:

  1. Down Payment: $57,600
  2. Amount Financed: $302,400
  3. Monthly Payment: $1,973.17
  4. Total Amount Spent: $767,941.20

Would you like more details or have any questions?

Here are five related questions to consider:

  1. How much interest will Jenelle pay over the life of the loan?
  2. What if the interest rate was 6% instead of 7%? How would that affect her monthly payment?
  3. How much would she save if she made an extra monthly payment of $500?
  4. What is the total amount of interest paid if Jenelle refinances her loan after 10 years?
  5. What is the impact of a 20% down payment instead of 16%?

Tip: Making extra payments towards your mortgage principal can reduce the total interest paid over the life of the loan.

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Math Problem Analysis

Mathematical Concepts

Finance
Percentages
Loan Amortization
Interest Rates

Formulas

Down Payment = Price of the Home × Down Payment Percentage
Amount Financed = Price of the Home - Down Payment
M = [P × r × (1 + r)^n] / [(1 + r)^n - 1] (Fixed-rate mortgage formula)
Total Amount Spent = (Monthly Payment × Total Payments) + Down Payment

Theorems

Amortization Formula

Suitable Grade Level

Grades 10-12