If a box of chocolates is divided among 28 children, they get 6 chocolates each. How many more chocolates would each get, if the number of the children was reduced by 7?

Let's break it down step by step.

1. **Find the total number of chocolates in the box:**

   Since each of the 28 children gets 6 chocolates, the total number of chocolates is:
   \[
   \text{Total chocolates} = 28 \times 6 = 168
   \]

2. **Now, reduce the number of children by 7:**

   If there are 7 fewer children, the new number of children is:
   \[
   28 - 7 = 21 \text{ children}
   \]

3. **Find how many chocolates each child would get if there are 21 children:**

   The total number of chocolates remains the same (168), so each of the 21 children would get:
   \[
   \text{Chocolates per child} = \frac{168}{21} = 8
   \]

4. **Determine how many more chocolates each child would get:**

   If originally each child got 6 chocolates, but now each child gets 8 chocolates, the difference is:
   \[
   8 - 6 = 2
   \]

So, each child would get **2 more chocolates** if the number of children were reduced by 7.

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Would you like more details or have any questions about this process? Here are some related questions for further exploration:

1. What happens if the number of chocolates per child is increased instead of reducing the number of children?
2. How would the solution change if the number of chocolates per child was doubled?
3. How can you use this approach to solve similar distribution problems?
4. If the total number of chocolates were increased, how would the number of chocolates per child change?
5. How can you represent this problem algebraically to generalize it?

**Tip:** To solve problems like this, always focus on first determining the total amount being divided, and then adjust the number of recipients to see how it changes the amount per recipient.

This problem shows how to calculate how many more chocolates each child would get if the number of children decreases from 28 to 21, while keeping the total number of chocolates constant. Step-by-step solution using division and multiplication. Suitable for students in Grades 4-6.

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