The problem from the image involves Sinta distributing chocolates to her friends, with a remaining amount each time. Let's break it down.

The information provided is as follows:

1. Sinta buys a certain amount of chocolates.
2. If she divides them equally among 4 friends, there are 2 chocolates left.
3. If she divides them equally among 5 friends, there are 2 chocolates left.
4. If she divides them equally among 8 friends, there are 6 chocolates left.
5. The total number of chocolates is less than 40.

We need to find how many chocolates Sinta initially bought.

This is a case of solving for a number that satisfies all the conditions:

• The number $x$ of chocolates leaves a remainder of 2 when divided by 4 and 5.
• The number $x$ leaves a remainder of 6 when divided by 8.
• The number $x$ is less than 40.

Let's solve this step by step.

The conditions can be written as:

1. $x \equiv 2 \pmod{4}$
2. $x \equiv 2 \pmod{5}$
3. $x \equiv 6 \pmod{8}$

I'll solve this and get back to you with the exact number of chocolates Sinta bought.It seems that using a direct symbolic method for solving the modular system isn't possible in this case. However, we can use a more direct numerical approach to find the solution by checking for values of $x$ that satisfy all three modular conditions (less than 40).

Let me compute this another way.