Math Problem Statement

[2171 + 48] mod 5

Solution

We need to compute (2171+48)mod5(2171 + 48) \mod 5.

First, let's add 21712171 and 4848:

2171+48=22192171 + 48 = 2219

Now, we compute 2219mod52219 \mod 5. This is done by dividing 22192219 by 55 and finding the remainder.

2219÷5=443 remainder 42219 \div 5 = 443 \text{ remainder } 4

So, 2219mod5=42219 \mod 5 = 4.

Thus, [2171+48]mod5=4[2171 + 48] \mod 5 = 4.

Would you like further explanation or any additional details?

Here are 5 related questions you might find helpful:

  1. How is modular arithmetic used in computer science?
  2. How can we simplify modular arithmetic problems?
  3. What is the general form of a modular equation?
  4. How would the result change if we used mod3\mod 3 instead of mod5\mod 5?
  5. What is the significance of prime numbers in modular arithmetic?

Tip: In modular arithmetic, you can simplify large numbers before calculating by reducing each term mod nn first!

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Math Problem Analysis

Mathematical Concepts

Modular Arithmetic
Addition

Formulas

(a + b) mod n = [(a mod n) + (b mod n)] mod n

Theorems

Modular Arithmetic Properties

Suitable Grade Level

Grades 8-10