Math Problem Statement

In a particular country the number of retirees was approximately 150 per thousand people aged 20-64 in the first year of keeping that data. Forty years later, this number rose to approximately 200, and it was projected to rise to 275 after 50 years. Model N as a piecewise linear function of the time t in years since the first year, letting t = 0 represent the first year of keeping data. Then use your model to project the number of retires per thousand people aged 20-64 in year 47. (Round your answer to the nearest integer.)

Solution

We are asked to model N(t)N(t), the number of retirees per thousand people aged 20-64, as a piecewise linear function of tt, where t=0t = 0 represents the first year of data collection. The data points provided are:

  • At t=0t = 0 (the first year), N(0)=150N(0) = 150.
  • At t=40t = 40, N(40)=200N(40) = 200.
  • At t=50t = 50, N(50)=275N(50) = 275.

To model N(t)N(t), we can split the problem into two linear segments:

  1. The first segment covers 0t400 \leq t \leq 40.
  2. The second segment covers 40t5040 \leq t \leq 50.

Step 1: Equation of the first line for 0t400 \leq t \leq 40

We need to find the equation of the line passing through the points (0,150)(0, 150) and (40,200)(40, 200).

The slope m1m_1 of the line is given by: m1=200150400=5040=1.25m_1 = \frac{200 - 150}{40 - 0} = \frac{50}{40} = 1.25

Using the point-slope form of a linear equation: N(t)=m1t+N(0)N(t) = m_1 t + N(0) N(t)=1.25t+150for0t40N(t) = 1.25 t + 150 \quad \text{for} \quad 0 \leq t \leq 40

Step 2: Equation of the second line for 40t5040 \leq t \leq 50

We now find the equation of the line passing through (40,200)(40, 200) and (50,275)(50, 275).

The slope m2m_2 of this line is: m2=2752005040=7510=7.5m_2 = \frac{275 - 200}{50 - 40} = \frac{75}{10} = 7.5

Again, using the point-slope form: N(t)=m2(t40)+200N(t) = m_2 (t - 40) + 200 N(t)=7.5(t40)+200for40t50N(t) = 7.5 (t - 40) + 200 \quad \text{for} \quad 40 \leq t \leq 50 N(t)=7.5t300+200N(t) = 7.5 t - 300 + 200 N(t)=7.5t100for40t50N(t) = 7.5 t - 100 \quad \text{for} \quad 40 \leq t \leq 50

Step 3: Projection for year t=47t = 47

Since t=47t = 47 falls within the second segment (40t50)(40 \leq t \leq 50), we use the second equation: N(47)=7.5×47100=352.5100=252.5N(47) = 7.5 \times 47 - 100 = 352.5 - 100 = 252.5 Rounding to the nearest integer: N(47)=253N(47) = 253

Thus, the projected number of retirees per thousand people aged 20-64 in year 47 is 253\boxed{253}.

Do you want further clarification or details on any steps?

Here are 5 related questions:

  1. How would the result change if the rate of increase between years 40 and 50 was slower?
  2. What is the significance of using a piecewise linear function in modeling this data?
  3. How could this model be extended beyond 50 years?
  4. What assumptions underlie the use of a linear model in this context?
  5. How does the choice of rounding affect the final result?

Tip: When modeling real-world data, always check if linear functions are appropriate for the entire domain or if non-linear models might better reflect the situation.

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Math Problem Analysis

Mathematical Concepts

Piecewise Linear Functions
Linear Interpolation
Algebra

Formulas

Slope formula: m = (y2 - y1) / (x2 - x1)
Point-slope form: y = m(x - x1) + y1
Linear equation for first segment: N(t) = 1.25t + 150 for 0 <= t <= 40
Linear equation for second segment: N(t) = 7.5t - 100 for 40 <= t <= 50

Theorems

Linear function properties
Point-slope form of a line

Suitable Grade Level

Grades 9-12