Math Problem Statement

Consider this scenario: A town has an initial population of 75,000. It grows at a constant rate of 3,000 per year for 6 years. Find the linear function that models the town's population P as a function of the year t where t is the number of years since the model began.

If the function P is graphed, find the t-intercept. (The answer may be outside of the reasonable domain.)

(tP) =      

Interpret the t-intercept.

 years before the tracking of the population, the population was zero.

If the function P is graphed, find the P-intercept.

(tP) =      

Interpret the P-intercept.

The population at the  ---Select--- end beginning of tracking was  

Solution

Step 1: Define the Linear Function

Given:

  • Initial population P0=75,000P_0 = 75,000
  • Growth rate r=3,000r = 3,000 people per year
  • Time tt is the number of years since the model began

The population P(t)P(t) as a function of time tt can be expressed as a linear equation:

P(t)=rt+P0P(t) = r \cdot t + P_0

Substituting the given values:

P(t)=3,000t+75,000P(t) = 3,000 \cdot t + 75,000

Step 2: Find the tt-Intercept

The tt-intercept occurs when the population P(t)=0P(t) = 0. To find this:

0=3,000t+75,0000 = 3,000 \cdot t + 75,000

Solve for tt:

3,000t=75,0003,000 \cdot t = -75,000 t=75,0003,000=25t = \frac{-75,000}{3,000} = -25

So, the tt-intercept is t=25t = -25. In coordinate form:

(t,P)=(25,0)(t, P) = (-25, 0)

Interpretation of the tt-Intercept

The tt-intercept represents the time when the population would have been zero. So, 25 years before the tracking of the population began, the population would have been zero.

Step 3: Find the PP-Intercept

The PP-intercept occurs when t=0t = 0, which is the initial population:

P(0)=3,0000+75,000=75,000P(0) = 3,000 \cdot 0 + 75,000 = 75,000

So, the PP-intercept is P=75,000P = 75,000. In coordinate form:

(t,P)=(0,75,000)(t, P) = (0, 75,000)

Interpretation of the PP-Intercept

The PP-intercept represents the population at the beginning of tracking, which was 75,000.

Summary

  • The linear function is P(t)=3,000t+75,000P(t) = 3,000 \cdot t + 75,000.
  • The tt-intercept is (t,P)=(25,0)(t, P) = (-25, 0), meaning the population would have been zero 25 years before tracking began.
  • The PP-intercept is (t,P)=(0,75,000)(t, P) = (0, 75,000), representing the population at the beginning of tracking, which was 75,000.

Would you like more details on any part of the solution? Here are some related questions:

  1. How would the function change if the growth rate were different?
  2. What is the population after 10 years?
  3. How would you model this if the growth rate were not constant?
  4. How does the slope of the graph represent the rate of population growth?
  5. What would the population be in 50 years?

Tip: In linear functions, the slope tells you the rate of change (e.g., growth or decline), and the intercept tells you the starting point.

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Math Problem Analysis

Mathematical Concepts

Algebra
Linear Functions
Intercepts

Formulas

Linear function formula: P(t) = r * t + P0
Finding t-intercept: Set P(t) = 0 and solve for t
Finding P-intercept: Set t = 0 and solve for P(t)

Theorems

Linear function properties
Intercept interpretation

Suitable Grade Level

Grades 8-10