Math Problem Statement

Vessed contains liquid of Pand & in the ratio 5:3 It 16 thes of mixtwee are removed and the same quantity of liquid Q is added the ratio becomes Vessel had

Solution

It seems there are a few typos or missing details in your question. Let me clarify the situation and then work through the problem step by step.

Here’s what I understand so far:

  • A vessel contains a mixture of liquids PP and QQ in the ratio 5:3.
  • 16 liters of the mixture are removed.
  • After removing 16 liters, the same quantity (16 liters) of liquid QQ is added.
  • The ratio of PP to QQ changes, but you haven’t provided the new ratio or other details about the result.

To solve, I'll assume the following:

  • The initial volumes of liquids PP and QQ are in the ratio 5:3.
  • After removing 16 liters, the ratio of PP and QQ changes due to adding 16 liters of liquid QQ.

Could you clarify what the new ratio is, or provide any missing information?

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Math Problem Analysis

Mathematical Concepts

Ratio and Proportion
Mixture Problems
Basic Algebra

Formulas

Initial ratio of P and Q: 5:3
Quantity removed and added: 16 liters
New ratio formula after addition of Q

Theorems

Concept of mixture and replacement

Suitable Grade Level

Grades 8-10