Math Problem Statement

answer these

answer these

Solution

The problem you shared involves finding the missing sides of right-angled triangles using the Pythagorean Theorem. Let's solve each part step by step.

Problem 1:

a) Find the length of x:

The sides of the triangle are 3.4 cm and 5.1 cm. This is a right-angled triangle, so we apply the Pythagorean theorem:

a2+b2=c2a^2 + b^2 = c^2

where a=3.4cma = 3.4 \, \text{cm}, b=5.1cmb = 5.1 \, \text{cm}, and c=xc = x (the hypotenuse). We need to find xx.

3.42+5.12=x23.4^2 + 5.1^2 = x^2 11.56+26.01=x211.56 + 26.01 = x^2 37.57=x237.57 = x^2 x=37.576.1cmx = \sqrt{37.57} \approx 6.1 \, \text{cm}

b) Find the length of y:

The triangle has sides of 6 m and 8 m. We need to find the missing side yy, which is the hypotenuse.

Using the Pythagorean theorem again:

62+82=y26^2 + 8^2 = y^2 36+64=y236 + 64 = y^2 100=y2100 = y^2 y=100=10my = \sqrt{100} = 10 \, \text{m}

c) Find the length of z:

This is another right-angled triangle with legs 3 mm and 4 mm. We use the Pythagorean theorem to find zz (the hypotenuse):

32+42=z23^2 + 4^2 = z^2 9+16=z29 + 16 = z^2 25=z225 = z^2 z=25=5mmz = \sqrt{25} = 5 \, \text{mm}

Problem 2:

a) Find the length of d:

The triangle has sides of 6.4 mm and 10.2 mm. We apply the Pythagorean theorem:

6.42+10.22=d26.4^2 + 10.2^2 = d^2 40.96+104.04=d240.96 + 104.04 = d^2 145=d2145 = d^2 d=14512.0mmd = \sqrt{145} \approx 12.0 \, \text{mm}

b) Find the length of e:

The triangle has sides 8 cm and 12 cm. We need to find the missing side ee, which is the hypotenuse:

82+122=e28^2 + 12^2 = e^2 64+144=e264 + 144 = e^2 208=e2208 = e^2 e=20814.4cme = \sqrt{208} \approx 14.4 \, \text{cm}

c) Find the length of f:

This triangle has sides of 11 cm and 14.1 cm. We need to find ff (the hypotenuse):

112+14.12=f211^2 + 14.1^2 = f^2 121+198.81=f2121 + 198.81 = f^2 319.81=f2319.81 = f^2 f=319.8117.9cmf = \sqrt{319.81} \approx 17.9 \, \text{cm}

Summary of Answers:

  1. a) x6.1cmx \approx 6.1 \, \text{cm} b) y=10my = 10 \, \text{m} c) z=5mmz = 5 \, \text{mm}

  2. a) d12.0mmd \approx 12.0 \, \text{mm} b) e14.4cme \approx 14.4 \, \text{cm} c) f17.9cmf \approx 17.9 \, \text{cm}

Let me know if you'd like any further explanations or help with additional questions!

Here are a few more related questions to deepen the topic:

  1. How do you use the Pythagorean theorem when you only know one leg of the triangle and the hypotenuse?
  2. What happens if the triangle is not a right-angled triangle? How do you find the missing sides?
  3. Can the Pythagorean theorem be used in non-Euclidean geometry?
  4. What is the distance formula and how does it relate to the Pythagorean theorem?
  5. How do you apply the Pythagorean theorem to find the diagonal of a rectangle?

Tip: The Pythagorean theorem only works for right-angled triangles, so always verify that the triangle is a right-angled one before applying it!

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Math Problem Analysis

Mathematical Concepts

Geometry
Pythagorean Theorem

Formulas

a^2 + b^2 = c^2

Theorems

Pythagorean Theorem

Suitable Grade Level

Grades 7-9