Math Problem Statement

We are tasked with constructing a rectangular box with a volume of 13 cubic feet. The material for the top costs 9 dollars per square foot, the material for the four sides costs 4 dollars per square foot, and the material for the bottom costs 11 dollars per square foot. To the nearest cent, what is the minimum cost for such a box?

Solution

To find the minimum cost for constructing the rectangular box, we need to consider the dimensions and the costs associated with each surface of the box.

Let:

  • xx be the length,
  • yy be the width, and
  • hh be the height of the box.

Given:

  1. Volume constraint: xyh=13x \cdot y \cdot h = 13 cubic feet.
  2. Cost per square foot:
    • Top: 99 dollars per square foot
    • Bottom: 1111 dollars per square foot
    • Four sides: 44 dollars per square foot each

Step 1: Calculate Surface Areas

  • Top area: xyx \cdot y
  • Bottom area: xyx \cdot y
  • Four sides area: 2(xh)+2(yh)2(x \cdot h) + 2(y \cdot h)

Step 2: Calculate Cost for Each Part

  1. Cost of the top: 9(xy)9 \cdot (x \cdot y)
  2. Cost of the bottom: 11(xy)11 \cdot (x \cdot y)
  3. Cost of the four sides: 4[2(xh)+2(yh)]=8(xh+yh)4 \cdot [2(x \cdot h) + 2(y \cdot h)] = 8(x \cdot h + y \cdot h)

Step 3: Total Cost Function

The total cost CC is given by: C=9(xy)+11(xy)+8(xh+yh)C = 9(x \cdot y) + 11(x \cdot y) + 8(x \cdot h + y \cdot h) C=20(xy)+8(xh+yh)C = 20(x \cdot y) + 8(x \cdot h + y \cdot h)

Step 4: Substitute hh in Terms of xx and yy

Using the volume constraint xyh=13x \cdot y \cdot h = 13: h=13xyh = \frac{13}{x \cdot y}

Substitute hh into the cost function: C=20(xy)+8(x13xy+y13xy)C = 20(x \cdot y) + 8\left(x \cdot \frac{13}{x \cdot y} + y \cdot \frac{13}{x \cdot y}\right) C=20(xy)+813(x+y)xyC = 20(x \cdot y) + 8 \cdot \frac{13(x + y)}{x \cdot y} C=20(xy)+104(x+y)xyC = 20(x \cdot y) + \frac{104(x + y)}{x \cdot y}

Step 5: Optimization

To find the minimum cost, we would take partial derivatives of CC with respect to xx and yy, set them to zero, and solve for xx and yy. This is a calculus-based optimization problem.

Let me proceed with these calculations to determine the minimum cost.The critical point that is real and relevant to our problem (since dimensions must be positive real values) is:

x=y=261/352/35x = y = \frac{26^{1/3} \cdot 5^{2/3}}{5}

Let's calculate this approximate value and use it to determine the corresponding height hh and the minimum cost.The optimal dimensions for minimizing the cost of the box are approximately:

  • x=1.73x = 1.73 feet
  • y=1.73y = 1.73 feet
  • h=4.33h = 4.33 feet

The minimum cost to construct this box is approximately $180.09.

Would you like more details on how these values were derived, or do you have any further questions?

Here are five related questions to deepen your understanding:

  1. How does the cost function change if the price for one side varies?
  2. What if the volume constraint was different—how would that affect the minimum cost?
  3. How can the method of Lagrange multipliers be applied to similar optimization problems?
  4. Can we use a similar approach to minimize surface area for a fixed cost?
  5. How do changes in unit costs impact the dimensions of the box?

Tip: For optimization problems with constraints, expressing one variable in terms of others using the constraint can simplify the solution process significantly.

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Math Problem Analysis

Mathematical Concepts

Calculus
Optimization
Geometry

Formulas

Volume of a box: V = x * y * h
Surface area and cost calculations
Cost function optimization with constraints

Theorems

Optimization using partial derivatives
Volume constraint in optimization problems

Suitable Grade Level

College level (Calculus or advanced high school mathematics)