Math Problem Statement

Minimize C = 2x + 2y with the following constraints. y is less than or equal to 6 4x-2y is less than or equal to 8 2x+7 is greater than or equal to 6

Solution

To minimize the objective function C=2x+2yC = 2x + 2y subject to the given constraints, we'll follow these steps:

1. Identify the constraints:

  • y6y \leq 6
  • 4x2y84x - 2y \leq 8
  • 2x+762x + 7 \geq 6

2. Simplify the constraints if needed:

  • The third constraint 2x+762x + 7 \geq 6 simplifies to 2x12x \geq -1 or x12x \geq -\frac{1}{2}.

3. Write the constraints in standard form:

  • y6y \leq 6
  • 4x2y84x - 2y \leq 8 or 2xy42x - y \leq 4
  • x12x \geq -\frac{1}{2}

4. Graph the constraints and identify the feasible region:

  • The inequality y6y \leq 6 is a horizontal line at y=6y = 6, with the area below it included.
  • The inequality 2xy42x - y \leq 4 can be rewritten as y2x4y \geq 2x - 4.
  • The inequality x12x \geq -\frac{1}{2} is a vertical line at x=12x = -\frac{1}{2}, with the area to the right included.

The feasible region will be the area where all these constraints overlap.

5. Determine the vertices of the feasible region:

To find the vertices where the constraints intersect:

  1. Intersection of y=6y = 6 and y=2x4y = 2x - 4: 6=2x4    2x=10    x=56 = 2x - 4 \implies 2x = 10 \implies x = 5 Vertex: (5,6)(5, 6)

  2. Intersection of y=2x4y = 2x - 4 and x=12x = -\frac{1}{2}: y=2(12)4=14=5y = 2\left(-\frac{1}{2}\right) - 4 = -1 - 4 = -5 Vertex: (12,5)\left(-\frac{1}{2}, -5\right)

  3. Intersection of y=6y = 6 and x=12x = -\frac{1}{2}: Vertex: (12,6)\left(-\frac{1}{2}, 6\right)

6. Evaluate the objective function at each vertex:

Substitute the vertices into the objective function C=2x+2yC = 2x + 2y:

  1. At (5,6)(5, 6): C=2(5)+2(6)=10+12=22C = 2(5) + 2(6) = 10 + 12 = 22

  2. At (12,5)\left(-\frac{1}{2}, -5\right): C=2(12)+2(5)=110=11C = 2\left(-\frac{1}{2}\right) + 2(-5) = -1 - 10 = -11

  3. At (12,6)\left(-\frac{1}{2}, 6\right): C=2(12)+2(6)=1+12=11C = 2\left(-\frac{1}{2}\right) + 2(6) = -1 + 12 = 11

7. Conclusion:

The minimum value of CC is 11-11, which occurs at the vertex (12,5)\left(-\frac{1}{2}, -5\right).

Questions

  1. How would the feasible region change if the constraint y6y \leq 6 was changed to y<6y < 6?
  2. What would happen to the optimal solution if the coefficient of xx in the objective function C=2x+2yC = 2x + 2y was increased?
  3. How does the solution change if the constraint 2x+762x + 7 \geq 6 is replaced with 2x+7=62x + 7 = 6?
  4. How can you verify the feasibility of a solution in a linear programming problem?
  5. What would be the effect of changing the objective function to C=2x+3yC = 2x + 3y?

Tip

In linear programming, always ensure that you clearly define the feasible region by graphing the constraints, as the minimum or maximum values of the objective function will always occur at one of the vertices of this region.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Linear Programming
Constraints
Objective Functions

Formulas

-

Theorems

-

Suitable Grade Level

Advanced High School