Math Problem Statement

solve everything using graphing utility

The average cost per hour in dollars of producing x riding lawn mowers is given by the following: C(x) = 0.6x^2 + 19x - 262 + 2700/x. (a) Use a graphing utility to determine the number of riding lawn mowers to produce in order to minimize average cost. (b) What is the minimum average cost?

Solution

I have opened the image. Let's focus on solving the problem as specified:

The given cost function is: C(x)=0.6x2+19x262+2700x\overline{C}(x) = 0.6x^2 + 19x - 262 + \frac{2700}{x} where C(x)\overline{C}(x) represents the average cost per hour in dollars for producing xx riding lawn mowers.

We need to solve two parts using a graphing utility:

  1. Determine the number of riding lawn mowers that minimizes the average cost.
  2. Find the minimum average cost.

Let me handle these steps using a graphing method for optimization.It seems like I can’t do more advanced data analysis right now. Please try again later.

However, you can use any graphing utility like Desmos or a graphing calculator to plot the function and determine the minimum value visually. Here's how you can proceed:

  1. Plot the function C(x)=0.6x2+19x262+2700x\overline{C}(x) = 0.6x^2 + 19x - 262 + \frac{2700}{x} on a graphing tool.

  2. Look for the value of xx where the function reaches its lowest point. This value will be the number of lawn mowers that minimize the average cost.

If you need any help setting up the graph or interpreting it, let me know!

Do you have any questions? Here are five follow-up questions to expand your understanding:

  1. What is the general method for finding the minimum or maximum of a function algebraically?
  2. How can you verify the minimum cost using calculus?
  3. What does the term "average cost" mean in this context?
  4. How does adding the term 2700x\frac{2700}{x} affect the cost function?
  5. Why is it important to round to the nearest whole number for practical purposes?

Tip: To quickly estimate the minimum value, set the derivative of the cost function to zero and solve for xx.

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Math Problem Analysis

Mathematical Concepts

Quadratic Functions
Optimization
Rational Functions

Formulas

C(x) = 0.6x^2 + 19x - 262 + 2700/x

Theorems

First Derivative Test for Minima and Maxima
Quadratic Optimization

Suitable Grade Level

Grade 10-12