Math Problem Statement
Boundaries Limit Test Cummulative
x f Xm LB UB LL HL <CF >CF 56 - 5135 243 2595.5 55.5 5135.5 56 5135 243 259 5136 - 10215 11 7675.5 5135.5 10215.5 5136 10215 254 16 10216 - 15295 1 12755.5 10215.5 15295.5 10216 15295 255 5 15296 - 20375 1 17835.5 15295.5 20375.5 15296 20375 256 4 20376 - 25455 2 22915.5 20375.5 25455.5 20376 25455 258 3 25456 - 30535 0 27995.5 25455.5 30535.5 25456 30535 258 1 30536 - 35615 0 33075.5 30535.5 35615.5 30536 35615 258 1 35616 - 40695 0 38155.5 35615.5 40695.5 35616 40695 258 1 40696 - 45772 1 43234 40695.5 45772.5 40696 45772 259 1 259 USING THESE DATA, COMPUTE FOR MEDIAN CLASS AND MEDIAN
Solution
To compute the median class and the median from the given data, we will follow the steps below:
Step 1: Identify the total cumulative frequency (CF)
From the data, the total cumulative frequency is already provided as 259.
Step 2: Determine the position of the median
The formula for determining the median position is:
This means the median lies in the class where the cumulative frequency first exceeds 129.5.
Step 3: Locate the median class
Looking at the cumulative frequency column, we need to find the class where the cumulative frequency first surpasses 129.5:
- The first cumulative frequency greater than 129.5 is 243, which corresponds to the class 56 - 5135.
Thus, the median class is 56 - 5135.
Step 4: Apply the formula for the median
The formula for calculating the median is:
Where:
- = lower boundary of the median class = 55.5
- = total frequency = 259
- = cumulative frequency before the median class = 0 (since the median class is the first one)
- = frequency of the median class = 243
- = class width = 5135.5 - 55.5 = 5080
Substitute the values into the formula:
Now let's compute that.
The median is approximately 2762.74.
Summary:
- Median class: 56 - 5135
- Median: 2762.74
Would you like more details or have any questions about this process?
Here are some follow-up questions to deepen understanding:
- How does changing the class width affect the median?
- What happens if the frequencies were more evenly distributed across classes?
- How would we calculate the mode from this data?
- Can the median be computed if the data is presented in a different form, like a list of individual values?
- How can we verify the accuracy of this median calculation?
Tip: The median is less affected by extreme values (outliers) compared to the mean, making it a robust measure of central tendency in skewed distributions.
Ask a new question for Free
By Image
Drop file here or Click Here to upload
Math Problem Analysis
Mathematical Concepts
Statistics
Median
Class Intervals
Cumulative Frequency
Formulas
Median = L + [(N/2 - F) / f] * h
Where L = lower boundary of median class, N = total frequency, F = cumulative frequency before the median class, f = frequency of the median class, h = class width
Theorems
Median calculation for grouped data
Suitable Grade Level
Grades 10-12