Math Problem Statement

TT2.pdf

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ca n you work out all those problems

Solution

The file contains a series of tutorial problems in mechanics. Here's a breakdown of the problems:


Problem 1

Express forces P1P_1 and P2P_2 in terms of unit vectors i\mathbf{i} and j\mathbf{j}.

  • Answer: P1=192i422jNP_1 = -192\mathbf{i} - 422\mathbf{j} \, \text{N}, P2=1.28i+0.96jkNP_2 = 1.28\mathbf{i} + 0.96\mathbf{j} \, \text{kN}.

Problem 2

Determine the resultant RR of two forces acting on the hook using graphical, geometrical, and algebraic methods.

  • Answer: R=6.7i+10jkNR = -6.7\mathbf{i} + 10\mathbf{j} \, \text{kN}. Alternatively, R=12kN;θ=124R = 12 \, \text{kN}; \theta = 124^\circ.

Problem 3

Resolve the force PP into components along axes aa and bb.

  • Answer: Pa=6N;Pb=16NP_a = 6 \, \text{N}; P_b = 16 \, \text{N}.

Problem 4

Determine the magnitude of PP, given Px=200NP_x = 200 \, \text{N}.

  • Answer: P=224NP = 224 \, \text{N}.

Problem 5

Replace a 600 N force with a 400 N force in the negative yy-direction and another force FF. Find the magnitude and direction of FF.

  • Answer: F=872N;θ=53.4F = 872 \, \text{N}; \theta = 53.4^\circ.

Problem 6

Replace force PP with forces P1P_1 and P2P_2. P1P_1 is along the aaa-a direction, and P2=42kNP_2 = 42 \, \text{kN}. Find P1P_1 and the direction of P2P_2.

  • Answer: Two possible solutions:
    • P1=38N;θ=52P_1 = 38 \, \text{N}; \theta = -52^\circ
    • P1=7N;θ=8P_1 = 7 \, \text{N}; \theta = -8^\circ.

Problem 7

Express the resultant RR of two forces acting on the frame in vector form. If RR is applied through point EE, determine the vertical distance ss of EE from the base.

  • Answer: R=13i+2.5jkNR = 13\mathbf{i} + 2.5\mathbf{j} \, \text{kN}, vertical distance s=2.5ms = 2.5 \, \text{m}.

Do you need detailed step-by-step solutions for any of these problems?

Five follow-up questions:

  1. How do you break a force into its ii- and jj-components?
  2. What is the geometric method for finding the resultant of two forces?
  3. How do you resolve forces into non-orthogonal axes?
  4. Why is the magnitude of the force PP greater than the given component PxP_x?
  5. How do you use vector addition to replace forces?

Tip: Always check if the forces are perpendicular when resolving or summing forces, as it simplifies calculations.

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Math Problem Analysis

Mathematical Concepts

Vector Components
Resultant Forces
Force Resolution
Magnitude and Direction of Forces
Vector Addition

Formulas

Force Vector Components: F = Fx i + Fy j
Resultant Force: R = √(Rx^2 + Ry^2)
Angle of Resultant Force: θ = tan^(-1)(Ry / Rx)

Theorems

Pythagorean Theorem
Trigonometric Functions

Suitable Grade Level

University Level