Math Problem Statement
Solution
Let's start by addressing both questions shown in the image:
Question 3: Compute the mean and variance of the probability distribution
Given the probability distribution:
Mean (Expected Value) Formula:
Variance Formula:
First, compute :
Now, subtract :
So, the mean is , and the variance is .
Question 4: Discrete and Continuous Variables
- Discrete Random Variables: These variables take on distinct, countable values.
- Continuous Random Variables: These can take on any value within a given range (infinite possible values).
Classification:
- a. The number of new accounts established by a salesperson in a year: Discrete
- b. The time between customer arrivals to a bank ATM: Continuous
- c. The number of customers in Big Nick’s barber shop: Discrete
- d. The amount of fuel in your car’s gas tank: Continuous
- e. The number of minorities on a jury: Discrete
- f. The outside temperature today: Continuous
Do you want more detailed steps or have any questions about these answers?
Here are 5 related questions you might find helpful:
- How do you compute the standard deviation from variance?
- What are some real-world applications of expected value?
- Can a random variable be both discrete and continuous?
- How would you calculate the mean if the probabilities do not sum to 1?
- What is the role of probability distributions in decision-making?
Tip: Always check that the sum of the probabilities in a distribution equals 1 to ensure it's valid.
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Math Problem Analysis
Mathematical Concepts
Probability Distribution
Mean (Expected Value)
Variance
Discrete Random Variables
Continuous Random Variables
Formulas
Mean formula: μ = Σ(x_i * P(x_i))
Variance formula: σ^2 = Σ(x_i^2 * P(x_i)) - μ^2
Theorems
-
Suitable Grade Level
Grades 10-12
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