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We are given the following information about Gabriella's three number cards:

- The minimum is 21.
- The range is 38.
- The median is 43.

To find the mean, let's first determine the three numbers. Denote the three cards as \( a \), \( b \), and \( c \), where \( a \leq b \leq c \).

1. Since the median is 43, we know that \( b = 43 \), because the median is the middle value of the three numbers.
2. The range is the difference between the maximum and minimum values, so \( c - a = 38 \). Since the minimum \( a = 21 \), we can solve for \( c \) as follows:
   \[
   c - 21 = 38 \quad \Rightarrow \quad c = 21 + 38 = 59.
   \]

Thus, the three numbers are \( a = 21 \), \( b = 43 \), and \( c = 59 \).

To find the mean, we calculate the average of these three numbers:
\[
\text{Mean} = \frac{21 + 43 + 59}{3} = \frac{123}{3} = 41.
\]

Therefore, the mean of Gabriella's three cards is 41.

Would you like more details or have any questions? 

Here are five related questions:
1. How do you calculate the median for an even number of values?
2. What is the relationship between range, minimum, and maximum values?
3. How would the problem change if the range were reduced by 10?
4. Can the mean of a set of numbers be lower than its median? Why or why not?
5. What is the effect of outliers on the mean and median of a dataset?

**Tip:** When calculating the mean, ensure you correctly sum all values and then divide by the number of values to avoid errors.

Gabriella has three number cards. The minimum of her three cards is 21, the range is 38, and the median is 43. What is the mean of Gabriella's three cards?

Learn how to calculate the mean of Gabriella's three cards given the minimum value of 21, a range of 38, and a median of 43. This problem covers key statistical concepts, including mean, range, and median. Suitable for students in Grades 6-8.

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