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The question asks about the relationship between the mean, median, and mode based on the distribution of student ages in a table. The options are:

- A) mode < median < mean
- B) mode < mean < median
- C) median < mode < mean
- D) mean < mode < median

**Direct Answer**: The correct answer is **A) mode < median < mean**.

Would you like further details or have any questions? 

Here are 5 related questions to extend your understanding:
1. How do you calculate the mean, median, and mode from a frequency distribution?
2. What are the differences between mean, median, and mode in a skewed distribution?
3. How do changes in a dataset affect the relationship between mean, median, and mode?
4. Can the mean ever be less than both the median and mode? If so, in what kind of distribution?
5. Why is the median often a better measure of central tendency in skewed distributions?

**Tip**: In a positively skewed distribution, the mean is usually greater than the median, which in turn is greater than the mode.

The table above shows the distribution of ages of the 20 students enrolled in a college class. Which of the following gives the correct order of the mean, median, and mode of the ages?

Understand the relationship between mean, median, and mode in a distribution of student ages in a college class. This problem involves statistical concepts and skewness in distributions. Learn how to calculate central tendencies and their order based on data.

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