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The question in the image is asking you to find the mean for the number of students who work full-time, given that 22% of all students work full-time and the sample size is 16.

This is a problem related to **binomial distribution**, where the mean \( \mu \) of a binomial distribution can be calculated using the formula:

\[
\mu = n \cdot p
\]

Where:
- \( n \) is the sample size (16),
- \( p \) is the probability of success (22%, or 0.22 in decimal form).

### Calculation:
\[
\mu = 16 \cdot 0.22 = 3.52
\]

Thus, the mean number of students who work full-time is **3.52**.

The correct answer is **A. 3.52**.

Would you like further details or have any other questions?

Here are 5 related questions:
1. What is the variance in this binomial distribution?
2. How would you calculate the standard deviation for this distribution?
3. What if the probability was 30% instead of 22%, how would the mean change?
4. How does sample size affect the mean in a binomial distribution?
5. How do you interpret the result in terms of real-world scenarios?

**Tip:** In binomial problems, the mean gives an expected number of successes based on the probability and sample size.

According to a college survey, 22% of all students work full time. Find the mean for the number of students who work full time in samples of size 16.

Solve a problem based on a college survey showing that 22% of students work full time. Learn how to calculate the mean for students who work full time in a sample size of 16 using the binomial distribution formula.

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