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The question asks for the maximum value of the function \( \sqrt{x} \) on the interval \( I = [1, 4] \).

To solve this, let's analyze the function:

- The function \( f(x) = \sqrt{x} \) is increasing because as \( x \) increases, \( \sqrt{x} \) also increases.
- On the interval \( [1, 4] \), the minimum value of \( f(x) \) occurs at \( x = 1 \), which gives \( \sqrt{1} = 1 \).
- The maximum value of \( f(x) \) occurs at \( x = 4 \), which gives \( \sqrt{4} = 2 \).

Therefore, the maximum value of \( \sqrt{x} \) on the interval \( [1, 4] \) is **2**, which corresponds to option **e**.

Would you like further details or clarifications?

Here are 5 related questions to deepen understanding:
1. What is the domain of the function \( \sqrt{x} \)?
2. How does the function \( \sqrt{x} \) behave as \( x \) approaches infinity?
3. What would the maximum value be if the interval was \( [0, 4] \)?
4. How would the answer change if we were looking for the minimum value instead?
5. Can you explain how the derivative of \( \sqrt{x} \) confirms that it is an increasing function?

**Tip:** The square root function is defined only for non-negative numbers, and it increases monotonically for \( x \geq 0 \).

Nilai maksimum dari √x pada selang I = [1, 4] adalah...

Discover how to find the maximum value of the function √x on the interval [1, 4]. Learn about the monotonicity of the square root function and how it behaves over specific intervals. This problem is suitable for students in Grades 8-10.

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