Math Problem Statement

Determine the maximum number of turning points on the graph of f(x) = 2x^3 + 3x^2 + 3.

Solution

To determine the maximum number of turning points for the function f(x)=2x3+3x2+3f(x) = 2x^3 + 3x^2 + 3, we can use the following rule:

For a polynomial function of degree nn, the maximum number of turning points is n1n - 1.

Solution:

  1. The degree of f(x)=2x3+3x2+3f(x) = 2x^3 + 3x^2 + 3 is 3 (since the highest power of xx is 3).
  2. Applying the rule, the maximum number of turning points is 31=23 - 1 = 2.

Answer:

The graph of ff has a maximum of 2 turning points.

Would you like further details on the solution or have any other questions?

Related Questions:

  1. What is the degree of a polynomial and how does it affect the shape of the graph?
  2. How do you find the actual turning points of a polynomial function?
  3. What is the difference between a turning point and an inflection point?
  4. How does the leading coefficient influence the end behavior of a polynomial graph?
  5. How can we determine whether each turning point is a local maximum or minimum?

Tip:

To locate actual turning points, take the derivative of the function and find where it equals zero. Then, use the second derivative test to classify each turning point as a maximum or minimum.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Algebra
Polynomial Functions
Turning Points

Formulas

Maximum number of turning points for a polynomial function of degree n is n - 1

Theorems

Degree of a polynomial and turning points relationship

Suitable Grade Level

Grades 10-12