Math Problem Statement
n Exercises 25 through 30, find the maximum possibe order for an element of Sn for a given value of n. 25. n=5
Solution
To determine the maximum possible order of an element in , we need to analyze the cycle structure of elements in . The order of an element in is given by the least common multiple (LCM) of the lengths of the disjoint cycles in its cycle decomposition.
For , the maximum order will correspond to the LCM of cycle lengths that sum up to . Let’s consider the possibilities:
Step 1: Possible Cycle Decompositions
The partitions of (the ways of splitting ) are:
- (one 5-cycle)
- (a 4-cycle and a 1-cycle)
- (a 3-cycle and a 2-cycle)
- (a 3-cycle and two 1-cycles)
- (two 2-cycles and one 1-cycle)
- (a 2-cycle and three 1-cycles)
- (five 1-cycles)
Step 2: Compute LCM of Cycle Lengths
For each case:
- :
- :
- :
- :
- :
- :
- :
Step 3: Maximum Order
The maximum LCM occurs in case , giving:
Conclusion:
The maximum possible order of an element in is 6, achieved by an element with a cycle structure of .
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Related Questions:
- What is the general formula to determine the maximum order of elements in ?
- How is the LCM used in finding the order of a permutation in ?
- Can the cycle structure achieve the maximum order for ?
- What is the significance of partitions in understanding ?
- How does the order of elements in relate to group theory concepts like subgroup structure?
Tip:
To compute the order of an element in , always focus on finding the least common multiple of cycle lengths in its cycle decomposition.
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Math Problem Analysis
Mathematical Concepts
Group Theory
Permutations
Cycle Structure
Least Common Multiple (LCM)
Formulas
Order of an element in S_n = LCM of the lengths of disjoint cycles
Theorems
Properties of symmetric groups (S_n)
LCM property in permutations
Suitable Grade Level
Undergraduate - Introductory Abstract Algebra
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