Math Problem Statement

The depth, h(t), metres, of water at the entrance to a harbour at t hours after midnight on a particular day is given by h(t) = 8 + 4 sin(πt/6), 0 ≤ t ≤ 24. (a) Find the maximum depth and the minimum depth of the water. (b) Find the values of t for which h(t) ≥ 8.

Solution

This problem involves the equation for the depth of water at the entrance of a harbor, given by:

h(t)=8+4sin(πt6)h(t) = 8 + 4 \sin\left(\frac{\pi t}{6}\right)

where h(t)h(t) is the depth of the water in meters, and tt is the time in hours after midnight (ranging from 0 to 24 hours).

Let's now proceed to the given parts of the problem.

(a) Find the maximum depth and the minimum depth of the water.

  • The function h(t)=8+4sin(πt6)h(t) = 8 + 4 \sin\left(\frac{\pi t}{6}\right) involves a sine function.
  • The sine function oscillates between -1 and 1. Hence, sin(πt6)\sin\left(\frac{\pi t}{6}\right) will also oscillate between -1 and 1.

Therefore:

  • The maximum value of sin(πt6)\sin\left(\frac{\pi t}{6}\right) is 1, leading to: hmax=8+4(1)=12 meters.h_{\text{max}} = 8 + 4(1) = 12 \text{ meters}.

  • The minimum value of sin(πt6)\sin\left(\frac{\pi t}{6}\right) is -1, leading to: hmin=8+4(1)=4 meters.h_{\text{min}} = 8 + 4(-1) = 4 \text{ meters}.

Thus, the maximum depth of water is 12 meters, and the minimum depth of water is 4 meters.

(b) Find the values of tt for which h(t)8h(t) \geq 8.

We are asked to find the times when the depth of water is greater than or equal to 8 meters. This implies:

h(t)8h(t) \geq 8

Substitute the expression for h(t)h(t):

8+4sin(πt6)88 + 4 \sin\left(\frac{\pi t}{6}\right) \geq 8

Subtract 8 from both sides:

4sin(πt6)04 \sin\left(\frac{\pi t}{6}\right) \geq 0

Now, divide by 4:

sin(πt6)0\sin\left(\frac{\pi t}{6}\right) \geq 0

The sine function is non-negative when its argument is between 0 and π\pi, which happens for values of tt where:

0πt6π0 \leq \frac{\pi t}{6} \leq \pi

Multiply both sides by 6:

0t60 \leq t \leq 6

Hence, h(t)8h(t) \geq 8 for tt in the range [0,6][0, 6] hours. The same condition holds for tt in the range [12,18][12, 18] hours due to the periodicity of the sine function.

Thus, the values of tt for which h(t)8h(t) \geq 8 are 0t60 \leq t \leq 6 and 12t1812 \leq t \leq 18.


Would you like further details on the steps, or do you have any questions about the solution? Here are some related questions for deeper understanding:

  1. How does the sine function's periodicity affect the depth of water over time?
  2. Can you calculate the value of h(t)h(t) at any specific time, such as t=3t = 3 hours?
  3. What would happen to the depth if the coefficient of the sine function were increased or decreased?
  4. How could this function be applied to model tides or ocean waves?
  5. Can you explore the behavior of the depth outside the time interval [0, 24] hours?

Tip: The sine function's period is 2π2\pi, which means it repeats its values every 2π units. Adjusting coefficients inside the sine function alters its frequency and amplitude.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Sine Function
Amplitude
Periodic Functions

Formulas

h(t) = 8 + 4 sin(πt/6)

Theorems

Properties of the Sine Function
Periodic Nature of Trigonometric Functions

Suitable Grade Level

Grades 10-12