Math Problem Statement

A stone is thrown directly upward from a height of 30 ft with an initial velocity of 60 ft/sec. The height of the stone, in feet, t seconds after it has been thrown is given by the function s(t)=-16tsquare+60t+30. Determine the time at which the stone reaches its maximum height and find the maximum height.

Solution

The height of the stone, s(t)s(t), is given by the quadratic function:

s(t)=16t2+60t+30s(t) = -16t^2 + 60t + 30

To determine the time at which the stone reaches its maximum height and to find the maximum height, we can follow these steps:

Step 1: Find the time of maximum height

Since the equation is quadratic, the graph of the function is a parabola. Because the coefficient of t2t^2 is negative (16-16), the parabola opens downwards, meaning the vertex of the parabola represents the maximum height.

The formula for the time at which a quadratic function ax2+bx+cax^2 + bx + c reaches its vertex is given by:

tmax=b2at_{\text{max}} = \frac{-b}{2a}

In this case:

  • a=16a = -16
  • b=60b = 60

Substitute these values into the formula:

tmax=602(16)=6032=1.875secondst_{\text{max}} = \frac{-60}{2(-16)} = \frac{-60}{-32} = 1.875 \, \text{seconds}

So, the stone reaches its maximum height at t=1.875t = 1.875 seconds.

Step 2: Find the maximum height

Now, substitute t=1.875t = 1.875 back into the height equation s(t)s(t) to find the maximum height:

s(1.875)=16(1.875)2+60(1.875)+30s(1.875) = -16(1.875)^2 + 60(1.875) + 30

First, calculate 1.87521.875^2:

1.8752=3.5156251.875^2 = 3.515625

Now substitute back:

s(1.875)=16(3.515625)+60(1.875)+30s(1.875) = -16(3.515625) + 60(1.875) + 30

Simplify each term:

s(1.875)=56.25+112.5+30s(1.875) = -56.25 + 112.5 + 30

s(1.875)=86.25feets(1.875) = 86.25 \, \text{feet}

Conclusion:

  • The stone reaches its maximum height at t=1.875t = 1.875 seconds.
  • The maximum height is 86.2586.25 feet.

Would you like more details on any of these steps?

Here are 5 related questions:

  1. What happens to the height of the stone after it reaches its maximum height?
  2. How can we calculate when the stone hits the ground?
  3. Can you find the velocity of the stone at any given time?
  4. How do you find the total time the stone is in the air?
  5. What is the significance of the coefficient -16 in the height equation?

Tip: The formula tmax=b2at_{\text{max}} = \frac{-b}{2a} is a quick way to find the maximum or minimum of any quadratic function, depending on the sign of aa.

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Math Problem Analysis

Mathematical Concepts

Quadratic Functions
Maxima and Minima
Projectile Motion

Formulas

s(t) = -16t^2 + 60t + 30
Time of maximum height: t_max = -b / (2a)
Maximum height: s(t_max) = -16(t_max)^2 + 60(t_max) + 30

Theorems

Vertex Formula for Quadratic Functions

Suitable Grade Level

Grades 9-11