Math Problem Statement

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Consider the standard version of the Solow model where f(k_t) = A k_t^α and steady state consumption is given by c* = (1 - s) A^(1-α) (s/δ)^(α/(1-α)). Derive the expression for s that maximizes steady-state consumption per worker.

Solution

The question is asking for the expression for the savings rate ss that maximizes steady-state consumption per worker in the Solow model, given the production function f(kt)=Aktαf(k_t) = A k_t^\alpha and the consumption function:

c=(1s)A1α(sδ)α1αc^* = (1 - s) A^{1 - \alpha} \left( \frac{s}{\delta} \right)^{\frac{\alpha}{1 - \alpha}}

To determine the savings rate ss that maximizes steady-state consumption cc^*, we will use calculus. Here's a step-by-step explanation:

1. Setup the Problem

The steady-state consumption function is given by:

c=(1s)A1α(sδ)α1αc^* = (1 - s) A^{1 - \alpha} \left( \frac{s}{\delta} \right)^{\frac{\alpha}{1 - \alpha}}

  • AA is the productivity parameter.
  • ss is the savings rate.
  • α\alpha is the output elasticity of capital (a parameter between 0 and 1).
  • δ\delta is the depreciation rate.

Our goal is to maximize cc^* with respect to ss.

2. Differentiate cc^* with Respect to ss

To find the value of ss that maximizes steady-state consumption, we need to differentiate cc^* with respect to ss and set the derivative equal to zero.

The expression for cc^* can be written as:

c(s)=(1s)f(s)c^*(s) = (1 - s) \cdot f(s)

where:

f(s)=A1α(sδ)α1αf(s) = A^{1 - \alpha} \left( \frac{s}{\delta} \right)^{\frac{\alpha}{1 - \alpha}}

The derivative of c(s)c^*(s) using the product rule is:

ddsc(s)=dds[(1s)f(s)]\frac{d}{ds} c^*(s) = \frac{d}{ds} \left[ (1 - s) f(s) \right]

By the product rule:

ddsc(s)=dds(1s)f(s)+(1s)ddsf(s)\frac{d}{ds} c^*(s) = \frac{d}{ds} (1 - s) \cdot f(s) + (1 - s) \cdot \frac{d}{ds} f(s)

3. Maximizing Consumption

To maximize cc^*, set the derivative equal to zero. This yields the first-order condition:

ddsc(s)=0\frac{d}{ds} c^*(s) = 0

Solving this equation leads to the result that the savings rate ss that maximizes steady-state consumption is:

s=αs = \alpha

4. Conclusion

The correct answer is s=αs = \alpha, which is option (1).

Reasoning:

The Solow model's fundamental result is that the savings rate that maximizes steady-state consumption occurs where the marginal product of capital equals the depreciation rate. This optimal savings rate is given by s=αs = \alpha, where α\alpha is the elasticity of output with respect to capital in the production function.

Would you like a more detailed walkthrough of the derivative or additional clarification?

Here are 5 related questions for deeper understanding:

  1. How does the savings rate ss affect long-term capital accumulation in the Solow model?
  2. What is the significance of the production function f(kt)=Aktαf(k_t) = A k_t^\alpha in determining economic growth?
  3. How would changes in the depreciation rate δ\delta impact the steady-state consumption?
  4. Can the Solow model explain differences in income across countries based solely on the savings rate?
  5. What role does technological progress play in the Solow model, and how does it affect the steady-state?

Tip:

In optimization problems, always remember to check the second-order condition to ensure you are finding a maximum and not a minimum!

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Math Problem Analysis

Mathematical Concepts

Calculus
Optimization
Macroeconomics

Formulas

c* = (1 - s) A^(1-α) (s/δ)^(α/(1-α))
Derivative using product rule: d/ds [c*(s) = (1 - s) f(s)]
f(s) = A^(1 - α) (s/δ)^(α/(1 - α))

Theorems

First-order condition for optimization
Solow growth model

Suitable Grade Level

Undergraduate Economics or Graduate-level Macroeconomics