Math Problem Statement

Given that production function y=x1(power 2)x2(power 2), let price of output be 3, price of input x1=w1 and price of input x2=w2. Determine the maximum profit of the firm

Solution

To determine the maximum profit for the firm, we need to consider the production function and the costs involved.

Step 1: Define the production function

Given the production function:

y=x12x22y = x_1^2 x_2^2

where:

  • yy is the output,
  • x1x_1 and x2x_2 are the inputs.

The prices are given as:

  • The price of output is 3 (i.e., the firm sells its output for 3 units of money per unit of output).
  • The price of input x1x_1 is w1w_1.
  • The price of input x2x_2 is w2w_2.

Step 2: Revenue

The revenue is simply the price of output multiplied by the quantity of output produced:

Revenue=3y=3x12x22\text{Revenue} = 3 \cdot y = 3 \cdot x_1^2 x_2^2

Step 3: Cost

The total cost of producing output is the cost of inputs:

Cost=w1x1+w2x2\text{Cost} = w_1 x_1 + w_2 x_2

Step 4: Profit

Profit is the difference between revenue and cost:

Profit=RevenueCost\text{Profit} = \text{Revenue} - \text{Cost} Profit=3x12x22(w1x1+w2x2)\text{Profit} = 3 \cdot x_1^2 x_2^2 - (w_1 x_1 + w_2 x_2)

Step 5: Maximizing Profit

To maximize profit, we need to take partial derivatives of the profit function with respect to x1x_1 and x2x_2, set them equal to zero, and solve for the optimal values of x1x_1 and x2x_2.

Partial derivative with respect to x1x_1:

Profitx1=6x1x22w1\frac{\partial \text{Profit}}{\partial x_1} = 6 x_1 x_2^2 - w_1

Set this equal to zero:

6x1x22w1=06 x_1 x_2^2 - w_1 = 0 x1=w16x22x_1 = \frac{w_1}{6 x_2^2}

Partial derivative with respect to x2x_2:

Profitx2=6x12x2w2\frac{\partial \text{Profit}}{\partial x_2} = 6 x_1^2 x_2 - w_2

Set this equal to zero:

6x12x2w2=06 x_1^2 x_2 - w_2 = 0 x2=w26x12x_2 = \frac{w_2}{6 x_1^2}

Step 6: Solving for x1x_1 and x2x_2

Now we have two equations:

  1. x1=w16x22x_1 = \frac{w_1}{6 x_2^2}
  2. x2=w26x12x_2 = \frac{w_2}{6 x_1^2}

Substitute the expression for x2x_2 into the equation for x1x_1:

x1=w16(w26x12)2x_1 = \frac{w_1}{6 \left( \frac{w_2}{6 x_1^2} \right)^2}

This equation can be solved to find the optimal values of x1x_1 and x2x_2, but the algebra is quite intensive. Alternatively, using methods such as substitution or numerical techniques could yield the precise values.

Step 7: Calculate Maximum Profit

Once we have the values for x1x_1 and x2x_2, we can substitute them back into the profit equation:

Profit=3x12x22(w1x1+w2x2)\text{Profit} = 3 \cdot x_1^2 x_2^2 - (w_1 x_1 + w_2 x_2)

This will give us the maximum profit of the firm.

Would you like me to proceed with numerical solutions for specific values of w1w_1 and w2w_2, or would you prefer to explore the solution process in more detail?

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Math Problem Analysis

Mathematical Concepts

Microeconomics
Profit Maximization
Calculus
Optimization

Formulas

y = x1^2 * x2^2
Revenue = 3 * y = 3 * x1^2 * x2^2
Cost = w1 * x1 + w2 * x2
Profit = Revenue - Cost = 3 * x1^2 * x2^2 - (w1 * x1 + w2 * x2)

Theorems

Optimization Theorem
First-order Conditions for Maximum

Suitable Grade Level

College-level Economics/Mathematics