Math Problem Statement
Kane Manufacturing has a division that produces two models of fireplace grates, x units of model A and y units of model B. To produce each model A grate requires 3 lb of cast iron and 6 min of labor. To produce each model B grate requires 4 lb of cast iron and 3 min of labor. The profit for each model A grate is $2.00, and the profit for each model B grate is $1.50. Also, 1000 lb of cast iron and 20 labor-hours are available for the production of fireplace grates per day.
Because of a backlog of orders for model A grates, Kane's manager had decided to produce at least 150 of these grates a day. Operating under this additional constraint, how many grates of each model should Kane produce to maximize profit?
Solution
We need to formulate this problem as a linear programming (LP) model in order to maximize Kane Manufacturing's profit, given the resource constraints and requirements for each model of fireplace grate. Here's the step-by-step process.
1. Define the variables:
Let:
- = the number of model A grates produced per day
- = the number of model B grates produced per day
2. Objective function:
The profit for model A is $2 per grate, and for model B is $1.50 per grate. We want to maximize the total profit: where is the total profit.
3. Constraints:
There are several constraints based on the available resources and the requirement for producing at least 150 model A grates.
Cast iron constraint:
Each model A grate uses 3 lb of cast iron, and each model B grate uses 4 lb of cast iron. The total cast iron available is 1000 lb. So:
Labor constraint:
Each model A grate requires 6 minutes of labor, and each model B grate requires 3 minutes of labor. There are 20 labor-hours available, which is equivalent to 1200 minutes. So:
Production constraint for model A:
The company has decided to produce at least 150 model A grates per day:
Non-negativity constraints:
The number of grates produced must be non-negative:
4. Formulation of the linear programming problem:
We now have the complete LP formulation:
subject to:
5. Solve the system:
To solve this linear programming problem, you can use methods like the graphical method (since there are only two variables) or use a simplex algorithm.
Graphical Solution Approach (Basic Outline):
- Plot the constraint inequalities on the -plane.
- Identify the feasible region where all the inequalities overlap.
- Evaluate the objective function at each corner (vertex) of the feasible region, because the maximum profit will occur at one of these points.
Finding the vertices:
- The intersection of the constraints will give us the vertices (corner points) of the feasible region.
- After determining the coordinates of these points, we evaluate the profit function at each vertex to find which combination maximizes profit.
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Math Problem Analysis
Mathematical Concepts
Linear Programming
Optimization
Inequalities
Formulas
Profit function: P = 2x + 1.5y
Cast iron constraint: 3x + 4y ≤ 1000
Labor constraint: 6x + 3y ≤ 1200
Minimum production constraint for model A: x ≥ 150
Theorems
Simplex Algorithm
Graphical Method for Linear Programming
Suitable Grade Level
Grades 11-12, College
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